이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define FAST ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);cerr.tie(0)
#define mp make_pair
#define xx first
#define yy second
#define pb push_back
#define pf push_front
#define popb pop_back
#define popf pop_front
#define all(x) x.begin(),x.end()
#define ff(i,a,b) for (int i = a; i < b; i++)
#define fff(i,a,b) for (int i = a; i <= b; i++)
#define bff(i,a,b) for (int i = b-1; i >= a; i--)
#define bfff(i,a,b) for (int i = b; i >= a; i--)
using namespace std;
long double typedef ld;
unsigned int typedef ui;
long long int typedef li;
pair<int,int> typedef pii;
pair<li,li> typedef pli;
pair<ld,ld> typedef pld;
vector<vector<int>> typedef graph;
unsigned long long int typedef ull;
//const int mod = 998244353;
const int mod = 1000000007;
//Note to self: Check for overflow
int up[200005];
bool wh[200005];
bool isbip=true;
int kolkosamlos=0;
stack<pair<int,pii>> stek;
void dsu(int a, int b)
{
int wa=wh[a],wb=wh[b];
while (up[a]>=0)
{
a=up[a];
wa^=wh[a];
}
while (up[b]>=0)
{
b=up[b];
wb^=wh[b];
}
if (a==b || !isbip)
{
if (!isbip || wa==wb) isbip=false,stek.push({-1,{-1,-1}}),stek.push({-1,{-1,-1}}),kolkosamlos+=2;
else stek.push({0,{0,0}}),stek.push({0,{0,0}});
}
else
{
if (up[a]<up[b]) swap(a,b);
stek.push({b,{up[b],wh[b]}});
stek.push({a,{up[a],wh[a]}});
if (wa==wb) wh[a]^=1;
up[b]+=up[a],up[a]=b;
}
}
void rollback()
{
int rep=2;
while (rep--)
{
auto it=stek.top(); stek.pop();
if (it.xx!=-1){
up[it.xx]=it.yy.xx,wh[it.xx]=it.yy.yy;
}
else
{
kolkosamlos--;
if (kolkosamlos==0) isbip=true;
}
}
}
void printstack()
{
vector<pair<int,pii>> sta;
while (!stek.empty())
{
sta.pb(stek.top());
stek.pop();
}
for (auto it : sta) cout<<it.xx<<": "<<it.yy.xx<<","<<it.yy.yy<<endl;
cout<<endl;
while (!sta.empty())
{
stek.push(sta.back());
sta.popb();
}
}
pii eds[200005];
int rmost[200005]; //prvi za koji zabrana [i,rmost[i]] daje bipartitivan graf
void binarna(int l, int r, int okle, int dokle) //popunjeni su [1,okle-1] i [r+1,n]
{
//cout<<"["<<okle<<","<<dokle<<"] se slika u ["<<l<<","<<r<<"]"<<endl;
//printstack();
if (okle>dokle) return;
if (l==r)
{
fff(i,okle,dokle) rmost[i]=l;
}
else
{
int mid=(l+r)/2;
fff(i,mid+1,r) dsu(eds[i].xx,eds[i].yy);
if (!isbip)
{
fff(i,mid+1,r) rollback();
binarna(mid+1,r,okle,dokle);
}
else
{
int mokle=okle,kokle=0; //mid [okle,dokle]
while (mokle<dokle)
{
dsu(eds[mokle].xx,eds[mokle].yy),kokle++;
if (!isbip) break; mokle++;
}
//dakle, [okle,mokle] predstavlja one koji SU bipartitivni, [mokle,dokle] one koji NISU
while (kokle--) rollback();
binarna(l,mid,okle,mokle);
fff(i,mid+1,r) rollback();
fff(i,okle,mokle) dsu(eds[i].xx,eds[i].yy);
binarna(mid+1,r,mokle+1,dokle);
fff(i,okle,mokle) rollback();
}
}
}
int main()
{
FAST;
int n,m,q; cin>>n>>m>>q;
fff(i,1,n) up[i]=-1,wh[i]=0; isbip=true;
fff(i,1,m) cin>>eds[i].xx>>eds[i].yy;
binarna(0,m,1,m);
while (!stek.empty()) rollback();
fff(i,1,m)
{
if (!isbip) rmost[i]=m+1;
dsu(eds[i].xx,eds[i].yy);
}
//fff(i,1,m) cout<<i<<": "<<rmost[i]<<endl;
while (q--)
{
int ll,rr; cin>>ll>>rr;
if (rr>=rmost[ll]) cout<<"NO\n";
else cout<<"YES\n";
}
/*fff(i,1,1000) up[i]=-1,wh[i]=0; isbip=true;
while (true)
{
string t; cin>>t;
if (t=="add")
{
int u,v; cin>>u>>v;
dsu(u,v);
}
else if (t=="rollback")
{
rollback();
}
else cout<<"unsupported command!"<<endl;
cout<<(isbip?"bipartite":"has odd cycle")<<endl;
}*/
}
//Note to self: Check for overflow
/*
3 3 0
1 2
2 3
3 1
4 4 0
1 2
2 3
3 4
4 1
*/
컴파일 시 표준 에러 (stderr) 메시지
Joker.cpp: In function 'void binarna(int, int, int, int)':
Joker.cpp:137:17: warning: this 'if' clause does not guard... [-Wmisleading-indentation]
137 | if (!isbip) break; mokle++;
| ^~
Joker.cpp:137:36: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'if'
137 | if (!isbip) break; mokle++;
| ^~~~~
Joker.cpp: In function 'int main()':
Joker.cpp:13:20: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
13 | #define fff(i,a,b) for (int i = a; i <= b; i++)
| ^~~
Joker.cpp:157:5: note: in expansion of macro 'fff'
157 | fff(i,1,n) up[i]=-1,wh[i]=0; isbip=true;
| ^~~
Joker.cpp:157:34: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
157 | fff(i,1,n) up[i]=-1,wh[i]=0; isbip=true;
| ^~~~~
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