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Submission #718893

# Submission time Handle Problem Language Result Execution time Memory
718893 2023-04-05T05:05:43 Z edenooo Weird Numeral System (CCO21_day1problem2) C++17
8 / 25
 38 ms 27824 KB 
#include<bits/stdc++.h>
using namespace std;

#define INF 1234567890
#define ll long long
#define SZ 60

bool rev;
ll N;
int K, Q, D, M;
int A[5001], n[SZ];
bool suf[SZ+1];
vector<int> X[1000000];
vector<pair<int, int> > Y[10001];
int dp[SZ][10001], DP[10001];
pair<int, int> P[10001];

int f(int i, int j)
{
	if (i >= SZ) return DP[j+5000];
	if (i > 0 && suf[i] && j == 0) return true;

	int &ret = dp[i][j+5000];
	if (ret != -1) return ret;
	ret = 0;

	// j+x = n[i] (mod K)인 x를 사용해야 한다.
	for(int x : X[((n[i]-j)%K+K)%K])
		if (f(i+1, (j+x-n[i])/K))
		{
			ret = 1;
			break;
		}
	return ret;
}

void G(int j)
{
	if (j == 0) return;
	auto [nj,x] = P[j+5000];
	G(nj);
	cout << (rev ? -x : x) << " ";
}

void g(int i, int j)
{
	if (i >= SZ) { G(j); return; }
	if (i > 0 && suf[i] && j == 0) return;

	for(int x : X[((n[i]-j)%K+K)%K])
		if (f(i+1, (j+x-n[i] >= 0 ? (j+x-n[i])/K : -((-(j+x-n[i])+K-1)/K))))
		{
			g(i+1, (j+x-n[i] >= 0 ? (j+x-n[i])/K : -((-(j+x-n[i])+K-1)/K)));
			cout << (rev ? -x : x) << " \n"[i==0];
			return;
		}
}

int main()
{
	ios::sync_with_stdio(0); cin.tie(0);
	cin.exceptions(ios::badbit | ios::failbit);
	cin >> K >> Q >> D >> M;
	for(int i=1; i<=D; i++)
		cin >> A[i];
	while(Q--)
	{
		// clear
		rev = false;
		for(int i=0; i<1000000; i++)
			X[i].clear();
		for(int i=0; i<10001; i++)
			Y[i].clear();
		memset(dp, -1, sizeof(dp));
		memset(DP, 0, sizeof(DP));

		cin >> N;
		if (N < 0)
		{
			rev = true;
			N = -N;
			for(int i=1; i<=D; i++)
				A[i] = -A[i];
		}
		for(int i=0; i<SZ; i++)
		{
			n[i] = N % K;
			N /= K;
		}
		suf[SZ] = true;
		for(int i=SZ-1; i>=0; i--)
			suf[i] = suf[i+1] && (n[i] == 0);

		for(int i=1; i<=D; i++)
			X[(A[i]%K+K)%K].push_back(A[i]);

		// 길이가 매우 길 수 있나? i >= 60에서는 BFS를 돌려 주자.
		// 전이 방향이 반대라서 그래프를 새로 만들어야 한다...
		for(int j=-5000; j<=5000; j++)
			for(int x : X[((0-j)%K+K)%K])
			{
				int nj = (j+x)/K;
				Y[nj+5000].push_back({j, x}); // j에서 x를 사용하면 nj로 갈 수 있다.
			}

		queue<int> q;
		q.push(0), DP[0+5000] = 1;
		while(!q.empty())
		{
			int j = q.front(); q.pop();
			for(auto [pj,x] : Y[j+5000]) // j로 올 수 있는 애들
			{
				if (DP[pj+5000]) continue;
				q.push(pj), DP[pj+5000] = 1, P[pj+5000] = {j, x};
			}
		}

		if (!f(0, 0)) cout << "IMPOSSIBLE\n";
		else g(0, 0); // 역추적

		if (rev)
			for(int i=1; i<=D; i++)
				A[i] = -A[i];
	}
	return 0;
}

Subtask #1
8.0 / 8.0

# Verdict Execution time Memory Grader output
1 Correct 26 ms 26580 KB OK
2 Correct 26 ms 26580 KB OK
3 Correct 24 ms 26580 KB OK
4 Correct 24 ms 26580 KB OK
5 Correct 24 ms 26624 KB OK
6 Correct 24 ms 26580 KB OK
7 Correct 24 ms 26604 KB OK
8 Correct 25 ms 26640 KB OK

Subtask #2
0 / 17.0

# Verdict Execution time Memory Grader output
1 Correct 26 ms 26580 KB OK
2 Correct 26 ms 26580 KB OK
3 Correct 24 ms 26580 KB OK
4 Correct 24 ms 26580 KB OK
5 Correct 24 ms 26624 KB OK
6 Correct 24 ms 26580 KB OK
7 Correct 24 ms 26604 KB OK
8 Correct 25 ms 26640 KB OK
9 Correct 30 ms 26672 KB OK
10 Correct 26 ms 26708 KB OK
11 Correct 32 ms 26720 KB OK
12 Correct 29 ms 26792 KB OK
13 Correct 38 ms 27824 KB OK
14 Correct 32 ms 27348 KB OK
15 Correct 33 ms 27240 KB OK
16 Incorrect 25 ms 26600 KB Query 1: Jury has an answer but participant does not
17 Halted 0 ms 0 KB -