이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define ll long long
#define pb push_back
#define all(v) v.begin(),v.end()
#define rall(v) v.rbegin(),v.rend()
#define sz(v) (int)v.size()
#define x first
#define y second
#define nl "\n"
using namespace std;
const int N = (int)1e5 + 7;
const int M = (int)2e6 + 5e5 + 7;
const ll MOD = (ll)1e9;
const int inf = (int)1e9 + 7;
const int B = (int)390;
const ll INF = (ll)1e18 + 7;
pair<int, int> dir[] = {{-1, 0}, {1, 0}, {0, 1}, {0, -1}};
bool bit(int mask, int i) {
return (mask >> i & 1);
}
int sum(int x, int y) {
x += y;
if(x >= MOD) x -= MOD;
return x;
}
int mult(int x, int y) {
return 1ll * x * y % MOD;
}
int n, k, a[N], suf[N], p[1001][201];
ll dp[1001][201];
void solve() {
cin >> n >> k;
for(int i = 1; i <= n; ++i) cin >> a[i];
for(int i = n; i >= 1; --i) suf[i] = suf[i + 1] + a[i];
ll ans = -INF;
int lst = -1;
for(int i = 1; i < n; ++i) {
for(int l = 1; l <= k; ++l) {
dp[i][l] = -INF;
for(int j = i; j >= 1; --j) {
if(dp[j - 1][l - 1] + (suf[j] - suf[i + 1]) * suf[i + 1] > dp[i][l]) {
dp[i][l] = dp[j - 1][l - 1] + (suf[j] - suf[i + 1]) * suf[i + 1];
p[i][l] = j;
}
}
}
if(dp[i][k] > ans) {
ans = dp[i][k];
lst = i;
}
}
assert(lst != -1);
vector<int> v;
while(lst > 0) {
v.pb(lst);
lst = p[lst][k--] - 1;
}
reverse(all(v));
cout << ans << nl;
for(auto x : v) cout << x << ' ';
}
signed main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
//freopen("sequence.in", "r", stdin);
//freopen("sequence.out", "w", stdout);
int test = 1;
//cin >> test;
for(int i = 1; i <= test; ++i) {
//cout << "Case " << i << ":\n";
solve();
}
return 0;
}
/*
possible causes of error :
* array bounds
* int overflow
* special case (n == 1?)
* haven't clean something
* wrong N | M | inf | INF | MOD
* try to write brute force to find test
* don't waste time
* don't write bullshit
* solution is easy
*/
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