Submission #71588

#TimeUsernameProblemLanguageResultExecution timeMemory
71588top34051Shortcut (IOI16_shortcut)C++17
93 / 100
1010 ms68676 KiB
#include "shortcut.h" #include<bits/stdc++.h> using namespace std; #define ll long long const int maxn = 1e5 + 5; const ll inf = 1e16; int n; ll cost, len[maxn], val[maxn]; ll pos[maxn]; int a[maxn], b[maxn]; ll tree[maxn]; void update(int t, int x, ll val) { while(x>0) { if(t==0) tree[x] = max(tree[x], val); else tree[x] = min(tree[x], val); x -= x&-x; } } ll query(int t, int x) { ll res = (t==0 ? -inf : inf); while(x<n) { if(t==0) res = max(res, tree[x]); else res = min(res, tree[x]); x += x&-x; } return res; } bool check(ll k) { // printf("check %lld\n",k); ll r1 = -inf, r2 = inf, c1 = -inf, c2 = inf; for(int i=0;i<n;i++) tree[i] = -inf; for(int i=0,j=-1;i<n;i++) { int x = a[i]; while(j+1<n && val[a[i]]-pos[a[i]] > k-(val[b[j+1]]+pos[b[j+1]])) { j++; int y = b[j]; update(0,y,pos[y]+val[y]); } r1 = max(r1, pos[x] + val[x] - k + cost + query(0,x+1)); c1 = max(c1, -pos[x] + val[x] - k + cost + query(0,x+1)); } for(int i=0;i<n;i++) tree[i] = inf; for(int i=0,j=-1;i<n;i++) { int x = a[i]; while(j+1<n && val[a[i]]-pos[a[i]] > k-(val[b[j+1]]+pos[b[j+1]])) { j++; int y = b[j]; update(1,y,pos[y]-val[y]); } r2 = min(r2, pos[x] - val[x] + k - cost + query(1,x+1)); c2 = min(c2, -pos[x] - val[x] + k - cost + query(1,x+1)); } if(r1 > r2 || c1 > c2) return 0; for(int i=0;i<n;i++) { ll L = max(r1-pos[i],c1+pos[i]), R = min(r2-pos[i],c2+pos[i]); int j = lower_bound(&pos[0],&pos[n],L) - &pos[0]; if(j<n && pos[j]<=R) return 1; } return 0; } ll solve() { for(int i=0;i<n-1;i++) pos[i+1] = pos[i] + len[i]; for(int i=0;i<n;i++) a[i] = b[i] = i; sort(&a[0],&a[n],[&](int x, int y){return val[x]-pos[x] < val[y]-pos[y];}); sort(&b[0],&b[n],[&](int x, int y){return val[x]+pos[x] > val[y]+pos[y];}); ll l = 0, r = inf, mid, res = -1; while(l<=r) { mid = (l+r)/2; if(check(mid)) { res = mid; r = mid-1; } else l = mid+1; } return res; } ll find_shortcut(int N, vector<int> l, vector<int> d, int c) { n = N; cost = c; for(int i=0;i<n-1;i++) len[i] = l[i]; for(int i=0;i<n;i++) val[i] = d[i]; return solve(); }
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