이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize ("O3")
#include <bits/stdc++.h>
using namespace std;
//------------------------------DEFINE------------------------------
//******************************************************************
#define IOS ios_base::sync_with_stdio(false); cin.tie(0),cout.tie(0)
#define ll long long
#define int long long
#define pb push_back
#define F first
#define S second
#define INF 1e18
#define all(v) (v).begin(),(v).end()
#define rall(v) (v).rbegin(),(v).rend()
#define pii pair<int,int>
#define pll pair<ll,ll>
#define OK cout<<"Ok"<<endl;
#define MOD (ll)(1e9+7)
#define endl "\n"
//******************************************************************
//----------------------------FUNCTION------------------------------
//******************************************************************
ll gcd(ll a,ll b){
if(a>b) swap(a,b);
if(a==0) return a+b;
return gcd(b%a,a);
}
ll lcm(ll a,ll b){
return a/gcd(a,b)*b;
}
bool is_prime(ll n){
ll k=sqrt(n);
if(n==2) return true;
if(n<2||n%2==0||k*k==n) return false;
for(int i=3;i<=k;i+=2){
if(n%i==0){
return false;
}
}
return true;
}
//*****************************************************************
//--------------------------MAIN-CODE------------------------------
const int mxn=2e5+5;
int t=1,n,m,arr[mxn],sub[mxn],sign[mxn],ans[mxn];
vector<int>vt[mxn];
bool f(int a,int b){
return arr[a]<arr[b];
}
bool check(int u){
priority_queue<pii,vector<pii>,greater<pii>>q;
ll ans=arr[u];
for(int v:vt[u]){
q.push({arr[v],v});
}
vector<int>color(n+5);
color[u]=1;
while(q.size()){
pii p=q.top();
q.pop();
int u=p.S;
ll sum=p.F;
if(color[u]) continue;
if(sum>ans) return false;
ans+=sum;
color[u]=1;
for(int v:vt[u]){
if(!color[v]){
q.push({arr[v],v});
}
}
}
for(int i=1;i<=n;i++){
if(!color[i]) return false;
}
return true;
}
void dfs(int u,int p){
for(int v:vt[u]){
if(v!=p){
dfs(v,u);
sub[u]+=sub[v];
if(sub[v]>=arr[u]){
sign[v]=1;
}
else{
sign[v]=0;
}
}
}
sub[u]+=arr[u];
}
void dfs2(int u,int p){
ans[u]=1;
for(int v:vt[u]){
if(v!=p){
if(sign[v]){
dfs2(v,u);
}
}
}
}
void solve2(){
dfs(1,-1);
dfs2(1,-1);
for(int i=1;i<=n;i++){
cout<<ans[i];
}
cout<<endl;
}
void solve(){
cin>>n>>m;
for(int i=1;i<=n;i++){
cin>>arr[i];
}
while(m--){
int a,b;
cin>>a>>b;
vt[a].pb(b);
vt[b].pb(a);
}
if(n>2000){
solve2();
return;
}
for(int i=1;i<=n;i++){
if(check(i)){
cout<<1;
}
else{
cout<<0;
}
}
cout<<endl;
}
signed main(){
IOS;
//cin>>t;
while(t--){
solve();
}
return 0;
}
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