oj.uz

답안 #714035

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
714035 2023-03-23T15:48:12 Z whqkrtk04 먼 별 (KOI16_dist) C++17
81 / 100
 393 ms 3304 KB 
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<int, pii> piii;
typedef pair<ll, ll> pll;
typedef pair<ll, pll> plll;
#define fi first
#define se second
const int INF = 1e9+1;
const int P = 1000000007;
const ll LLINF = (ll)1e18+1;
template <typename T>
istream& operator>>(istream& is, vector<T>& v) { for(auto &i : v) is >> i; return is; }
template <typename T1, typename T2>
ostream& operator<<(ostream& os, const pair<T1, T2>& p) { os << p.fi << " " << p.se; return os; }
template <typename T>
ostream& operator<<(ostream& os, const vector<T>& v) { for(auto i : v) os << i << " "; os << "\n"; return os; }
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
#define rnd(x, y) uniform_int_distribution<int>(x, y)(rng)

ll mod(ll a, ll b) { return ((a%b) + b) % b; }
ll ext_gcd(ll a, ll b, ll &x, ll &y) {
    ll g = a; x = 1, y = 0;
    if(b) g = ext_gcd(b, a % b, y, x), y -= a / b * x;
    return g;
}
ll inv(ll a, ll m) {
    ll x, y; ll g = ext_gcd(a, m, x, y);
    if(g > 1) return -1;
    return mod(x, m);
}

struct Point {
    ll x, y;
    Point(ll x, ll y) : x(x), y(y) {}
};
ostream& operator<<(ostream& out, Point a) {
    cout << '(' << a.x << ' ' << a.y << ')';
    return out;
}
int ccw(Point a, Point b, Point c) {
    ll x = (b.x - a.x) * (c.y - b.y) - (c.x - b.x) * (b.y - a.y);
    return (int)(x > 0) - (int)(x < 0);
}
bool operator<(Point a, Point b) {
    if (a.x == b.x) return a.y < b.y;
    return a.x < b.x;
}
bool operator>(Point a, Point b) {
    return b < a;
}
bool operator<=(Point a, Point b) {
    return (a < b) || (a.x == b.x && a.y == b.y);
}
Point operator-(Point a, Point b) {
	return {a.x - b.x, a.y - b.y};
}
ll operator/(Point a, Point b){
	return a.x * b.y - a.y * b.x;
}
bool intersect(Point p1, Point p2, Point p3, Point p4) {
    int r1 = ccw(p1, p2, p3) * ccw(p1, p2, p4);
    int r2 = ccw(p3, p4, p1) * ccw(p3, p4, p2);
    if (r1 == 0 && r2 == 0) {
        if (p1 > p2) swap(p1, p2);
        if (p3 > p4) swap(p3, p4);
        return (!(p2 < p3 || p4 < p1) ? 1 : 0);
    } else {
        return (r1 <= 0 && r2 <= 0 ? 1 : 0);
    }
}

ll dst(Point p, Point q) {
    return (p.x-q.x)*(p.x-q.x)+(p.y-q.y)*(p.y-q.y);
}

vector<Point> convex_hull(vector<Point> A) {
    assert(A.size() >= 2);
    vector<Point> hull;
    swap(A[0], *min_element(A.begin(), A.end()));
    sort(A.begin()+1, A.end(), [&](Point a, Point b) {
        ll cw = ccw(A[0], a, b);
        if(cw) return cw > 0;
        return dst(A[0], a) < dst(A[0], b);
    });
    for(auto &i : A) {
        while(hull.size() >= 2 && ccw(hull[hull.size()-2], hull.back(), i) <= 0) hull.pop_back();
        hull.push_back(i);
    }
    return hull;
}

ll rotating_calipers(vector<Point> A) {
	// A[0] should be mininum element, A should be a convex polygon and sorted in ccw
	int n = A.size(); A.push_back(A[0]);
	int l = 0, r = max_element(A.begin(), A.end()) - A.begin();
    ll ret = 0LL;
	while (1) {
	// A[l], A[r] are antipodal points
        // your code here
        ret = max(ret, dst(A[l], A[r]));
		if (n == 2 || r == n) break;
		if ((A[l + 1] - A[l]) / (A[r + 1] - A[r]) <= 0) {
			l += 1;
		}
		else r += 1;
	}
    return ret;
}

ll solve(int n, int t, vector<pii>& IXY, vector<pii>& DXY) {
    vector<Point> XY;
    for(int i = 0; i < n; i++) {
        Point p = {0, 0};
        p.x = IXY[i].fi+(ll)t*DXY[i].fi;
        p.y = IXY[i].se+(ll)t*DXY[i].se;
        XY.push_back(p);
    }
    vector<Point> hull = convex_hull(XY);
    return rotating_calipers(hull);
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    int n, t; cin >> n >> t;
    vector<pii> IXY(n), DXY(n);
    for(int i = 0; i < n; i++)
        cin >> IXY[i].fi >> IXY[i].se >> DXY[i].fi >> DXY[i].se;
    int l = 0, r = t;
    while(r-l >= 3) {
        int s = (l*2+r)/3, e = (l+r*2)/3;
        ll ss = solve(n, s, IXY, DXY);
        ll ee = solve(n, e, IXY, DXY);
        if(ss <= ee) r = e;
        else l = s;
    }
    int res = -1;
    ll ans = LLINF;
    for(int i = l; i <= r; i++) {
        ll tmp = solve(n, i, IXY, DXY);
        if(tmp < ans) ans = tmp, res = i;
    }
    assert(res != -1);
    cout << res << "\n" << ans << "\n";
    return 0;
}

Subtask #1
2.0 / 2.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 1 ms 212 KB Output is correct
4 Correct 1 ms 212 KB Output is correct
5 Correct 0 ms 212 KB Output is correct
6 Correct 1 ms 212 KB Output is correct
7 Correct 1 ms 212 KB Output is correct
8 Correct 1 ms 212 KB Output is correct
9 Correct 1 ms 212 KB Output is correct
10 Correct 0 ms 212 KB Output is correct

Subtask #2
40.0 / 40.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 1 ms 212 KB Output is correct
4 Correct 1 ms 212 KB Output is correct
5 Correct 0 ms 212 KB Output is correct
6 Correct 1 ms 212 KB Output is correct
7 Correct 1 ms 212 KB Output is correct
8 Correct 1 ms 212 KB Output is correct
9 Correct 1 ms 212 KB Output is correct
10 Correct 0 ms 212 KB Output is correct
11 Correct 8 ms 340 KB Output is correct
12 Correct 11 ms 428 KB Output is correct
13 Correct 7 ms 340 KB Output is correct
14 Correct 8 ms 340 KB Output is correct
15 Correct 9 ms 388 KB Output is correct
16 Correct 13 ms 340 KB Output is correct
17 Correct 7 ms 340 KB Output is correct
18 Correct 4 ms 340 KB Output is correct
19 Correct 6 ms 340 KB Output is correct
20 Correct 11 ms 340 KB Output is correct

Subtask #3
39.0 / 39.0

# 결과 실행 시간 메모리 Grader output
1 Correct 102 ms 1828 KB Output is correct
2 Correct 76 ms 1876 KB Output is correct
3 Correct 74 ms 1832 KB Output is correct
4 Correct 65 ms 3200 KB Output is correct
5 Correct 85 ms 1876 KB Output is correct
6 Correct 106 ms 3304 KB Output is correct
7 Correct 66 ms 1888 KB Output is correct
8 Correct 60 ms 1836 KB Output is correct
9 Correct 70 ms 3204 KB Output is correct
10 Correct 87 ms 1876 KB Output is correct

Subtask #4
0 / 19.0

# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 1 ms 212 KB Output is correct
4 Correct 1 ms 212 KB Output is correct
5 Correct 0 ms 212 KB Output is correct
6 Correct 1 ms 212 KB Output is correct
7 Correct 1 ms 212 KB Output is correct
8 Correct 1 ms 212 KB Output is correct
9 Correct 1 ms 212 KB Output is correct
10 Correct 0 ms 212 KB Output is correct
11 Correct 8 ms 340 KB Output is correct
12 Correct 11 ms 428 KB Output is correct
13 Correct 7 ms 340 KB Output is correct
14 Correct 8 ms 340 KB Output is correct
15 Correct 9 ms 388 KB Output is correct
16 Correct 13 ms 340 KB Output is correct
17 Correct 7 ms 340 KB Output is correct
18 Correct 4 ms 340 KB Output is correct
19 Correct 6 ms 340 KB Output is correct
20 Correct 11 ms 340 KB Output is correct
21 Correct 102 ms 1828 KB Output is correct
22 Correct 76 ms 1876 KB Output is correct
23 Correct 74 ms 1832 KB Output is correct
24 Correct 65 ms 3200 KB Output is correct
25 Correct 85 ms 1876 KB Output is correct
26 Correct 106 ms 3304 KB Output is correct
27 Correct 66 ms 1888 KB Output is correct
28 Correct 60 ms 1836 KB Output is correct
29 Correct 70 ms 3204 KB Output is correct
30 Correct 87 ms 1876 KB Output is correct
31 Correct 393 ms 1860 KB Output is correct
32 Correct 359 ms 1944 KB Output is correct
33 Incorrect 375 ms 1876 KB Output isn't correct
34 Halted 0 ms 0 KB -