This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define ll long long
#define ar array
#define db double
#define all(x) x.begin(), x.end()
#define sz(x) (int)x.size()
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
#define rint(l, r) uniform_int_distribution<int>(l, r)(rng)
template<typename T> bool ckmin(T &a, const T &b) { return a > b ? a = b, 1 : 0; }
template<typename T> bool ckmax(T &a, const T &b) { return a < b ? a = b, 1 : 0; }
struct fenwick {
int n;
vector<int> bit;
fenwick() {}
void resize(int a) {
n = a, bit.resize(a+1);
}
void update(int pos, int x) {
pos++;
for (; pos <= n; pos += pos&-pos) {
bit[pos] += x;
}
}
int sum(int pos) {
int s = 0;
while (pos) {
s += bit[pos], pos -= pos&-pos;
}
return s;
}
int query(int l, int r) {
return sum(r+1) - sum(l);
}
};
struct seg {
int N;
vector<fenwick> tree;
vector<vector<int>> vals;
vector<int> who;
vector<int> L, R;
seg(const vector<ar<int, 2>> &pts) {
int each = 1;
for (int i = 1; i < sz(pts); i++) each += pts[i][0] != pts[i-1][0];
N = 1<<(__lg(each)+1);
tree.resize(2*N), vals.resize(2*N), who.resize(each), L.resize(2*N, 1e9), R.resize(2*N, -1e9);
for (int i = 0, c = 0; i < sz(pts); i++, c++) {
int r = i;
while (r+1 < sz(pts) && pts[r+1][0] == pts[r][0]) r++;
for (int j = i; j <= r; j++) {
vals[c+N].push_back(pts[j][1]);
}
tree[c+N].resize(r-i+1), L[c+N] = pts[i][0], R[c+N] = pts[i][0];
who[c] = pts[i][0];
i = r;
}
for (int i = N-1; i >= 1; i--) {
merge(all(vals[i*2]), all(vals[i*2+1]), back_inserter(vals[i]));
vals[i].erase(unique(all(vals[i])), vals[i].end());
tree[i].resize(sz(vals[i]));
L[i] = min(L[i*2], L[i*2+1]);
R[i] = max(R[i*2], R[i*2+1]);
}
}
void update(int x, int y, int v) {
auto it = lower_bound(all(who), x);
assert(it != who.end() && *it == x);
int pos = it - who.begin();
for (int i = pos+N; i; i >>= 1) {
auto it2 = lower_bound(all(vals[i]), y);
assert(it2 != vals[i].end() && *it2 == y);
tree[i].update(it2 - vals[i].begin(), v);
}
}
int query(int node, int x, int y) {
if (R[node] < x) return 0;
if (L[node] >= x) {
auto it = lower_bound(all(vals[node]), y);
if (it != vals[node].end()) {
return tree[node].query(it - vals[node].begin(), sz(vals[node]) - 1);
}
return 0;
}
return query(node*2, x, y) + query(node*2+1, x, y);
}
};
void test_case() {
int n, q;
cin >> n >> q;
vector<ar<int, 2>> pts(n);
for (auto &x : pts) cin >> x[0] >> x[1];
vector<ar<int, 4>> queries(q);
for (auto &x : queries) cin >> x[0] >> x[1] >> x[2];
for (int i = 0; i < q; i++) queries[i][3] = i;
sort(all(queries), [&](const auto &A, const auto &B) { return A[2] > B[2]; });
sort(all(pts), [&](const auto &A, const auto &B) { return A[0]+A[1] > B[0]+B[1]; });
vector<int> ans(q);
int to = -1;
vector<ar<int, 2>> all_pts{pts};
for (int i = 0; i < q; i++) all_pts.push_back({queries[i][0], queries[i][1]});
sort(all(all_pts));
all_pts.erase(unique(all(all_pts)), all_pts.end());
seg st(all_pts);
for (int i = 0; i < q; i++) {
while (to+1 < n && pts[to+1][0] + pts[to+1][1] >= queries[i][2]) {
to++;
st.update(pts[to][0], pts[to][1], 1);
}
ans[queries[i][3]] = st.query(1, queries[i][0], queries[i][1]);
}
for (int i = 0; i < q; i++) cout << ans[i] << '\n';
}
int main() {
cin.tie(0)->sync_with_stdio(0);
int t = 1;
// cin >> t;
while (t--) test_case();
}
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