제출 #712685

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
712685		jcelin	Dijamant (COI16_dijament)	C++14	13 / 100	2050 ms	3740 KiB

dijament

#include <bits/stdc++.h>
//#include<ext/pb_ds/assoc_container.hpp>
//#include<ext/pb_ds/tree_policy.hpp>
 
using namespace std;
//using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
 
#define ii pair<int,int>
#define pll pair<ll,ll>
#define vi vector<int>
#define vii vector<ii>
#define vll vector<ll>
#define vpll vector<pll>
#define msi multiset<int>
#define si set<int>
#define PB push_back
#define PF push_front
#define PPB pop_back
#define PPF pop_front
#define X first
#define Y second
#define MP make_pair
#define FOR(i, a, b) for (int i = int(a); i < int(b); i++)
#define REP(i, n) FOR(i, 0, n)
#define all(x) (x).begin(), (x).end()
 
const int mod = 1e9 + 7;
const int MOD = 998244353;
const int inf = mod;
const ll INF = 1e18;
const int logo = 20;
const int MAXN = 1e3 + 7;
const int off = 1 << logo;
const int trsz = off << 1;
 
bitset<MAXN> cvis[MAXN][2], need[2];
vi g[MAXN], pg[MAXN], r[MAXN];
int nod = 1, pnod = 1, indeg[MAXN];
map<string, int> ids;
string fir;
vi inp;
string wa = "abc.+";
vi topo, st, sus;
 

void failalo(string &ad){
	FOR(i, 1, nod + 1) g[i] = pg[i], pg[i].clear(), r[i].clear(), cvis[i][0].reset(), cvis[i][1].reset(), indeg[i] = 0;	
	nod = pnod;
	ids[ad] = 0;
	need[0].reset();
	need[1].reset();
	cout << "greska\n";
}

 
void scan(int &a){
	a=0;
	char c=getchar_unlocked();
	while(c==10){
		c=getchar_unlocked();
	}
	while(c>='0' && c<='9'){
		a*=10;
		a+=c-'0';
		c=getchar_unlocked();
	}
}
 
void scanline(){
	fir.clear();
	inp.clear();
	char c = getchar_unlocked();
	while(c==10){
		c=getchar_unlocked();
	}
	while(c != ' ') fir.PB(c), c = getchar_unlocked();
	getchar_unlocked();
	getchar_unlocked();
	c = getchar_unlocked();
	while(c==10){
		c=getchar_unlocked();
	}
	string s1;
	while(c != ';'){
		while(c != ' ') s1.PB(c), c = getchar_unlocked();
		inp.PB(ids[s1]);
		s1.clear();
		c = getchar_unlocked();
	}
	getchar_unlocked();
}
 
 
 
void check(){
	pnod = nod;
	FOR(i, 1, nod + 1){
		pg[i] = g[i];
		indeg[i] = 0;
		r[i].clear();	
		cvis[i][0].reset();
		cvis[i][1].reset();
	}
	
	scanline();
	if(ids[fir]){
		failalo(wa);
		return;
	}
	
	ids[fir] = nod++;
	
	for(auto &cur : inp){
		if(!cur){
			failalo(wa);
			return;
		}
	}
	
	for(auto &x : inp) g[x].PB(nod - 1);
	
	FOR(j, 1, nod) for(auto &x : g[j]) indeg[x]++, r[x].PB(j);
	
	vi topo, st; topo.clear(), st.clear();
	FOR(j, 1, nod) if(indeg[j] == 0) st.PB(j);
	while(!st.empty()){
		int u = st.back();
		st.PPB();
		topo.PB(u);
		for(auto &x : g[u]) if(--indeg[x] == 0) st.PB(x);
	}
	
	
	for(auto &x : topo){
		cvis[x][0][x] = 1;
		for(auto &y : g[x]) cvis[y][0] |= cvis[x][0];
	}
	reverse(all(topo));
	for(auto &x : topo){
		cvis[x][1][x] = 1;
		for(auto &y : r[x]) cvis[y][1] |= cvis[x][1];
	}
	
	FOR(j, 1, nod) FOR(i, 1, j){
		if(cvis[i][1][j] or cvis[i][0][j]) continue;
		need[0] = cvis[i][1] & cvis[j][1];
		need[1] = cvis[i][0] & cvis[j][0];
		need[0][i] = 0;
		need[0][j] = 0;
		need[1][i] = 0;
		need[1][j] = 0;
		if(need[0].count() and need[1].count()){
			failalo(fir);
			return;
		}
	}
	
	cout << "ok\n";
}
 
void solve(){
	int n;
	scan(n);
	REP(i, n) check();
}
 
 
int main(){
	ios_base::sync_with_stdio(false);
	cin.tie(NULL);
	cout.tie(NULL);
	int t=1;
	//cin >> t;
	while(t--)solve();
	return 0;
}
 
 

• Subtask 1: 13 / 13
• Subtask 2: 0 / 14
• Subtask 3: 0 / 29
• Subtask 4: 0 / 44