이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx,popcnt,sse4,abm")
#include <bits/stdc++.h>
using namespace std;
#ifdef WAIMAI
#define debug(HEHE...) cout << "[" << #HEHE << "] : ", dout(HEHE)
void dout() {cout << '\n';}
template<typename T, typename...U>
void dout(T t, U...u) {cout << t << (sizeof... (u) ? ", " : ""), dout (u...);}
#else
#define debug(...) 7122
#endif
#define ll long long
#define Waimai ios::sync_with_stdio(false), cin.tie(0)
#define FOR(x,a,b) for (int x = a, I = b; x <= I; x++)
#define pb emplace_back
#define F first
#define S second
using point = pair<int, int>;
const int SIZE = 1e5 + 5;
int subtask, n, q;
point p[SIZE];
ll cross(point a, point b) {
return 1ll * a.F * b.S - 1ll * a.S * b.F;
}
point operator - (point a, point b) {
return point(a.F - b.F, a.S - b.S);
}
void solve() {
cin >> subtask >> n;
FOR (i, 1, n) cin >> p[i].F >> p[i].S;
cin >> q;
while (q--) {
point P;
cin >> P.F >> P.S;
bool f = 0;
FOR (i, 1, n / 2) {
auto p1 = p[i], p2 = p[i + 1];
auto p3 = p[i + n / 2], p4 = p[i + n / 2 + 1 > n ? 1 : i + n / 2 + 1];
if (cross(p1 - P, p2 - P) >= 0 && cross(p3 - P, p4 - P) >= 0) {
f = 1;
break;
}
}
cout << (f ? "DA" : "NE") << '\n';
}
}
int main() {
Waimai;
solve();
}
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