이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,abm,avx,mmx,popcnt,tune=native")
using namespace std;
const int mod = 1e6 + 7;
int n, dp[2][10002][2], p[10002];
void add (int &a, int b) {
a += b;
if (a >= mod)
a-= mod;
}
int main ()
{
ios_base::sync_with_stdio(false);
cin.tie(0); cout.tie(0);
cin >> n;
for (int i = 1; i <= n; i++)
cin >> p[i];
dp[0][0][1] = 1;
for (int i = 0; i < n; i++) {
int k = (i & 1);
for (int j = 0; j <= n; j++)
dp[k ^ 1][j][0] = dp[k ^ 1][j][1] = 0;
for (int j = 0; j <= i; j++) {
///1 lmao
if (j > 0)
add(dp[k ^ 1][j][1], dp[k][j][1] * (p[i + 1] <= j));
if (j < n)
add(dp[k ^ 1][j + 1][1], dp[k][j][1] * (j + 1 == p[i + 1]));
///0 lmao
if (j > 0) {
add(dp[k ^ 1][j][0], 1ll * dp[k][j][1] * min(j, p[i + 1] - 1) % mod);
add(dp[k ^ 1][j][0], 1ll * dp[k][j][0] * j % mod);
}
if (j < n) {
add(dp[k ^ 1][j + 1][0], dp[k][j][1] * (j + 1 < p[i + 1]));
add(dp[k ^ 1][j + 1][0], dp[k][j][0]);
}
}
}
int ans = 0;
for (int i = 1; i <= n; i++) {
add(ans, dp[n & 1][i][0]);
add(ans, dp[n & 1][i][1]);
}
cout << ans << "\n";
return 0;
}
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