제출 #710552

#제출 시각아이디문제언어결과실행 시간메모리
710552ssenseHorses (IOI15_horses)C++14
17 / 100
113 ms21936 KiB
#include <bits/stdc++.h> #include "horses.h" using namespace std; #define MOD 1000000007 int ng; vector<int> xg; vector<int> yg; long long pref = 1; int power(int n, int pow, int m) {if (pow == 0) return 1;if (pow % 2 == 0) {long long x = power(n, pow / 2, m);return (x * x) % m;}else return (power(n, pow - 1, m) * n) % m;} int init(int n, int* x, int* y) { ng = n; for(int i = 0; i < n; i++) { xg.push_back(x[i]); yg.push_back(y[i]); } for(int i = 0; i < ng-32; i++) { pref*=xg[i]; pref%=MOD; } int stop = 0; long long p = 1; for(int i = ng-1; i >= 0; i--) { p*=xg[i]; if(p > 1000000000) { stop = i; break; } } p = pref; for(int i = max(0, ng-32); i < stop; i++) { p*=xg[i]; p%=MOD; } long long mx = 0; long long p2 = 1; for(int i = stop; i < ng; i++) { p2*=xg[i]; if(mx < p2*yg[i]) { mx = p2*yg[i]; } } return (int)((mx*p)%MOD); } int updateX(int pos, int val) { if(pos < ng-32) { pref*=power(xg[pos], MOD-2, MOD); pref%=MOD; pref*=val; pref%=MOD; } xg[pos] = val; int stop = 0; long long p = 1; for(int i = ng-1; i >= 0; i--) { p*=xg[i]; if(p > 1000000000) { stop = i; break; } } p = pref; for(int i = max(0, ng-32); i < stop; i++) { p*=xg[i]; p%=MOD; } long long mx = 0; long long p2 = 1; for(int i = stop; i < ng; i++) { p2*=xg[i]; if(mx < p2*yg[i]) { mx = p2*yg[i]; } } mx%=MOD; return (int)((mx*p)%MOD); } int updateY(int pos, int val) { yg[pos] = val; int stop = 0; long long p = 1; for(int i = ng-1; i >= 0; i--) { p*=xg[i]; if(p > 1000000000) { stop = i; break; } } p = pref; for(int i = max(0, ng-32); i < stop; i++) { p*=xg[i]; p%=MOD; } long long mx = 0; long long p2 = 1; for(int i = stop; i < ng; i++) { p2*=xg[i]; if(mx < p2*yg[i]) { mx = p2*yg[i]; } } mx%=MOD; return (int)((mx*p)%MOD); }

컴파일 시 표준 에러 (stderr) 메시지

horses.cpp: In function 'int power(int, int, int)':
horses.cpp:13:127: warning: conversion from 'long long int' to 'int' may change value [-Wconversion]
   13 | int power(int n, int pow, int m) {if (pow == 0) return 1;if (pow % 2 == 0) {long long x = power(n, pow / 2, m);return (x * x) % m;}else return (power(n, pow - 1, m) * n) % m;}
      |                                                                                                                       ~~~~~~~~^~~
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