Submission #707657

# Submission time Handle Problem Language Result Execution time Memory
707657 2023-03-09T16:44:03 Z Johann Catfish Farm (IOI22_fish) C++17
Compilation error
0 ms 0 KB
#include "bits/stdc++.h"
using namespace std;

typedef long long ll;
typedef pair<ll, ll> pii;
typedef vector<ll> vi;
typedef vector<vi> vvi;
typedef vector<pii> vpii;
typedef vector<vpii> vvpii;
typedef map<ll, ll> mii;
typedef vector<mii> vmii;
#define sz(x) (int)(x).size()
#define all(x) (x).begin(), (x).end()

const ll INF = 3e5 * 1e9 + 100;

void updateIdx(ll y, ll &ny, mii::iterator &itpref0, ll &pref0)
{
    if (itpref0->first == y)
    {
        pref0 = itpref0->second;
        ++itpref0;
    }
    ny = min(itpref0->first, ny);
}

void printTable(vmii &grid, int N)
{
    for (int x = 0; x < sz(grid); ++x)
    {
        auto it = grid[x].begin();
        ll tmp, value;
        if (it == grid[x].end())
            return;
        for (int y = 0; y < N; ++y)
        {
            updateIdx(y, tmp, it, value);
            cout << value << "\t";
        }
        cout << "\n";
    }
}

long long max_weights(int N, int M, std::vector<int> X, std::vector<int> Y, std::vector<int> W)
{
    vmii grid(N + 4); // becomes prefix grid
    for (int x = 0; x < sz(grid); ++x)
        grid[x][0] = 0;

    for (int i = 0; i < M; ++i)
        grid[X[i] + 3][Y[i]] = W[i];

    for (int x = 0; x < sz(grid); ++x)
    {
        ll pref = 0;
        for (auto it = grid[x].begin(); it != grid[x].end(); ++it)
        {
            pref += it->second;
            it->second = pref;
        }
        grid[x][N] = pref;
    }

    vmii dpg(sz(grid));  // growth stack thing
    vmii dp(sz(grid));   // normal all dp
    vi dpm(sz(grid), 0); // maximum einer Spaltes
    for (int i = 0; i < 3; ++i)
        dpg[i][0] = dpg[i][N] = dp[i][0] = dp[i][N] = 0;

    for (int x = 3; x < sz(grid) - 1; ++x) // so i choose the borders
    {
        ll c1 = -INF, c2 = -INF; // running variables for case 1 and 2 // TODO: INIT
        ll y = 0, ny;
        ll pref0 = 0, pref1 = 0, pref2 = 0, dp0 = 0, dpg1 = 0;
        auto itpref0 = grid[x - 1].begin(); // idx for pref x-1
        auto itpref1 = grid[x].begin();     // idx for pref x
        auto itpref2 = grid[x + 1].begin(); // idx for pref x+1
        auto itdp0 = dp[x - 2].begin();     // idx for dp x-2
        auto itdpg1 = dpg[x - 1].begin();   // idx for dpg x-1
        while (y < N)
        {
            // update indices
            ny = INT_MAX;
            updateIdx(y, ny, itpref0, pref0);
            updateIdx(y, ny, itpref1, pref1);
            updateIdx(y, ny, itpref2, pref2);
            updateIdx(y, ny, itdp0, dp0);
            updateIdx(y, ny, itdpg1, dpg1);

            // Case 1 - last tower in x-1 and smaller y
            c1 = max(c1, dpg1 - pref0 - pref1);
            dpg[x][y] = max(dpg[x][y], pref0 + pref2 + c1);

            // Case 2 - last tower in x-2 and smaller y
            c2 = max(c2, dp0 - pref0);
            dpg[x][y] = max(dpg[x][y], pref0 + pref2 + c2);

            // Case 3 - last tower in x-1 and larger y (or if it is smaller, case 1 performs better)
            // here the last tower might be larger than the current one
            dp[x][y] = max(dp[x][y], dpm[x - 1] - pref1 + pref2);

            // Case 4 - Last Tower in x-2 and larger y (or if it is smaller, case 2 performs better)
            dpg[x][y] = max(dpg[x][y], dpm[x - 2] + pref2);

            // Case 5 - Last Tower in x-3
            dpg[x][y] = max(dpg[x][y], dpm[x - 3] + pref0 + pref2);

            // keep track for dpg & dpm
            dp[x][y] = max(dp[x][y], dpg[x][y]);
            dpm[x] = max(dpm[x], dp[x][y]);

            y = ny;
        }
        dp[x][N] = max(dp[x][N], dp[x].rbegin()->second);
        dpg[x][N] = max(dpg[x][N], dpg[x].rbegin()->second);
    }

    printTable(grid, N);
    cout << "______________________________\n\n";
    printTable(dpg, N);
    cout << "______________________________\n\n";
    printTable(dp, N);

    return *max_element(all(dpm));
}

int main()
{
    int N, M;
    assert(2 == scanf("%d %d", &N, &M));

    std::vector<int> X(M), Y(M), W(M);
    for (int i = 0; i < M; ++i)
    {
        assert(3 == scanf("%d %d %d", &X[i], &Y[i], &W[i]));
    }

    long long result = max_weights(N, M, X, Y, W);
    printf("%lld\n", result);
    return 0;
}

Compilation message

/usr/bin/ld: /tmp/ccYPVMpY.o: in function `main':
grader.cpp:(.text.startup+0x0): multiple definition of `main'; /tmp/ccRp47IZ.o:fish.cpp:(.text.startup+0x0): first defined here
collect2: error: ld returned 1 exit status