이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
const int N = 101010;
const int B = 404;
int n, m, q, u[N], v[N], w[N], s[N], t[N], y[N], z[N], weight[N], ans[N];
bool used[N], vis[N];
vector<int> g[N];
struct dsu {
int pp[N], sz[N];
void init() {
iota(pp, pp + N, 0);
fill(sz, sz + N, 1);
}
int find(int a) {
return pp[a] = ((pp[a] == a) ? a : find(pp[a]));
}
void merge(int a, int b) {
a = find(a); b = find(b);
if (a != b) {
pp[b] = a;
sz[a] += sz[b];
}
}
} d1;
int main() {
cin.tie(0); ios_base::sync_with_stdio(0);
cin >> n >> m;
for (int i = 1; i <= m; i++) {
cin >> u[i] >> v[i] >> w[i];
}
cin >> q;
for (int i = 1; i <= q; i++) {
cin >> t[i] >> y[i] >> z[i];
}
for (int i = 1; i <= m; i++)
s[i] = i;
vector<int> upd, ask;
for (int x = 1; x <= q; x++) {
if (t[x] == 1)
upd.push_back(x), used[y[x]] = 1;
else
ask.push_back(x);
if (upd.size() == B || x == q) {
sort(s + 1, s + 1 + m, [&](int i, int j) {
return w[i] > w[j];
});
sort(ask.begin(), ask.end(), [&](int i, int j) {
return z[i] > z[j];
});
vector<int> edges;
for (int i : upd)
edges.push_back(y[i]);
sort(edges.begin(), edges.end());
edges.erase(unique(edges.begin(), edges.end()), edges.end());
d1.init();
int p = 1;
for (auto i : ask) {
while (p <= m && w[s[p]] >= z[i]) {
if (!used[s[p]])
d1.merge(u[s[p]], v[s[p]]);
++p;
}
for (int j : edges)
weight[j] = w[j];
for (int j : upd) {
if (j <= i)
weight[y[j]] = z[j];
}
for (int j : edges) {
int a = d1.find(u[j]);
int b = d1.find(v[j]);
if (weight[j] >= z[i]) {
g[a].push_back(b);
g[b].push_back(a);
}
}
int x = d1.find(y[i]);
vector<int> q;
q.push_back(x);
int res = 0;
while (!q.empty()) {
int v = q.back(); q.pop_back();
if (vis[v])
continue;
vis[v] = 1;
res += d1.sz[v];
for (int x : g[v])
q.push_back(x);
}
for (int j : edges) {
int a = d1.find(u[j]);
int b = d1.find(v[j]);
g[a].clear();
g[b].clear();
vis[a] = 0;
vis[b] = 0;
}
ans[i] = res;
}
for (auto i : upd) {
used[i] = 0;
w[y[i]] = z[i];
}
upd.clear();
ask.clear();
}
}
for (int i = 1; i <= q; i++) {
if (t[i] == 2)
cout << ans[i] << '\n';
}
}
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