Submission #706778

#TimeUsernameProblemLanguageResultExecution timeMemory
706778epicci23Exhibition (JOI19_ho_t2)C++17
100 / 100
66 ms5588 KiB
#include "bits/stdc++.h" #pragma optimize ("Bismillahirrahmanirrahim") using namespace std; #define pb push_back #define ff first #define ss second #define endl "\n" #define int long long #define double long double #define sz(x) ((int)(x).size()) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define what_is(x) cerr << #x << " is " << x << endl; //#define m (l+r)/2 constexpr int N=200005; constexpr int MOD=1000000007; constexpr int INF2 = LLONG_MAX; constexpr int INF=(int)1e18; constexpr int LOG=30; typedef pair<int,int> pii; typedef tuple<int,int,int> tp; typedef priority_queue<pii,vector<pii>,greater<pii>> min_pq; typedef priority_queue<pii> max_pq; typedef long long ll; //to think// /* * graph approach * dp * dividing the problem to smaller statements * finding the real constraint * sqrt decomposition * greedy approach * pigeonhole principle * rewriting the problem/equality * bitwise approaches * binary search if monotonic * divide and conquer * combinatorics * inclusion - exclusion * think like bfs */ inline int in() { int x;cin >> x; return x; } inline string in2() { string x;cin >> x; return x; } void solve() { int n=in(),m=in(); vector<array<int,2>> v(n); for(int i=0;i<n;i++) v[i][1]=in(),v[i][0]=in(); vector<int> q(m); for(int i=0;i<m;i++) q[i]=in(); sort(all(q)); sort(all(v)); int l=0,r=min(n,m); while(l<r) { int mi=(l+r+1)/2; bool ok=1; int p=0; for(int i=m-mi;i<m;i++) { if(p==n) ok=0; while(p<n && v[p][1] > q[i]) p++; if(p==n) ok=0; p++; } if(ok) l=mi; else r=mi-1; } cout << l << endl; } int32_t main(){ cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(15); int t=1;//cin>> t; for(int i=1;i<=t;i++) { // cout << "Case #" << i << ": "; solve(); } return 0; }

Compilation message (stderr)

joi2019_ho_t2.cpp:2: warning: ignoring '#pragma optimize ' [-Wunknown-pragmas]
    2 | #pragma optimize ("Bismillahirrahmanirrahim")
      |
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