제출 #704504

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
704504		GrandTiger1729	Dango Maker (JOI18_dango_maker)	C++17	13 / 100	1 ms	324 KiB

dango_maker

#include <iostream>
#include <vector>
#include <functional>
using namespace std;

int main(){
    cin.tie(0)->sync_with_stdio(0);
    int n, m; cin >> n >> m;
    vector<pair<int, int>> ed;
    int N = 0;
    {
        string g[n];
        for (int i = 0; i < n; i++)
            cin >> g[i];
        vector<vector<int>> vis(n, vector<int>(m, -1));
        for (int i = 0; i < n; i++){
            for (int j = 0; j < m; j++){
                if (g[i][j] != 'W') continue;
                if (i - 1 >= 0 && g[i - 1][j] == 'G' && \
                        i - 2 >= 0 && g[i - 2][j] == 'R'){
                    vis[i][j] = vis[i - 1][j] = vis[i - 2][j] = N;
                    N++;
                }
            }
        }
        for (int j = 0; j < m; j++){
            for (int i = 0; i < n; i++){
                if (g[i][j] != 'W') continue;
                if (j - 1 >= 0 && g[i][j - 1] == 'G' && \
                        j - 2 >= 0 && g[i][j - 2] == 'R'){
                    if (vis[i][j] != -1)
                        ed.emplace_back(vis[i][j], N);
                    if (vis[i][j - 1] != -1)
                        ed.emplace_back(vis[i][j - 1], N);
                    if (vis[i][j - 2] != -1)
                        ed.emplace_back(vis[i][j - 2], N);
                    N++;
                }
            }
        }
    }
    vector<vector<int>> g(N);
    for (auto &[u, v]: ed){
        g[u].push_back(v);
        g[v].push_back(u);
    }
    vector<vector<int>> dp(N, vector<int>(2));
    vector<bool> vis(N);
    function<void(int)> dfs = [&](int u){
        vis[u] = 1;
        dp[u][1] = 1;
        for (auto &v: g[u]){
            if (vis[v]) continue;
            dfs(v);
            dp[u][0] += max(dp[v][0], dp[v][1]);
            dp[u][1] += dp[v][0];
        }
    };
    int ans = 0;
    for (int i = 0; i < N; i++){
        if (!vis[i]){
            dfs(i);
            ans += max(dp[i][0], dp[i][1]);
        }
    }
    cout << ans << '\n';
    return 0;
}

• Subtask 1: 13 / 13
• Subtask 2: 0 / 20
• Subtask 3: 0 / 67