이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#ifdef DEBUG
#include "debug.h"
#else
#define debug(x) void(37)
#endif
#define lsb(x) ((x)&(-x))
#define all(x) x.begin(),x.end()
#define setprec(n) cout << fixed << showpoint;cout << setprecision(n);
typedef long long ll;
typedef long double ld;
const ld eps = 1e-10;
const ll MOD1 = 1e9+7;
const ll MOD2 = 998244353;
const ll LINF = 1e18;
const int IINF = 1e9;
#define int ll
const int maxn = 355;
int n, k;
string str;
int dp[maxn][maxn][maxn];
int cm[maxn][maxn][maxn];
vector<int> pref, suff;
int go(int l, int r, int tk){
int turn = (n-(r-l)) % 2;
if(turn){ // branka's turn
int br = (suff[r] + pref[l]) - tk;
if(br >= k) return 0;
if(tk >= k) return 1;
int can = 0;
if(str[l] == 'C' && br + 1 < k) can |= !go(l+1, r, tk);
else if(str[l] != 'C') can |= !go(l+1, r, tk);
if(str[r-1] == 'C' && br + 1 < k) can |= !go(l, r-1, tk);
else if(str[r-1] != 'C') can |= !go(l, r-1, tk);
return can;
}
else{ // anton's turn
if(tk >= k) return 0;
if((suff[r] + pref[l]) - tk >= k) return 1;
if(cm[l][r][tk]) return dp[l][r][tk];
int can = 0;
if(str[l] == 'C' && tk + 1 < k) can |= !go(l+1, r, tk);
else if(str[l] != 'C') can |= !go(l+1, r, tk);
if(str[r-1] == 'C' && tk + 1 < k) can |= !go(l, r-1, tk);
else if(str[r-1] != 'C') can |= !go(l, r-1, tk);
cm[l][r][tk] = 1;
return dp[l][r][tk] = can;
}
}
void solve(){
cin >> n >> k;
cin >> str;
pref.resize(n+1), suff.resize(n+1);
for(int i = 1;i <= n;i++) pref[i] = pref[i-1] + (str[i-1] == 'C');
for(int i = n-1;i >= 0;i--) suff[i] = suff[i+1] + (str[i] == 'C');
if(go(0, n, 0)) cout << "DA" << "\n";
else cout << "NE" << "\n";
}
signed main(){
ios_base::sync_with_stdio(false); cin.tie(NULL);
mt19937 mt(time(NULL));
//setprec(10);
//freopen("sleepy.in", "r", stdin);
//freopen("in.txt", "w", stdout);
int t = 1;
//cin >> t;
for(int i = 1;i <= t;i++)
solve();
return 0;
}
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