제출 #703841

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
703841		bebra	슈퍼트리 잇기 (IOI20_supertrees)	C++17	21 / 100	194 ms	22180 KiB

supertrees

#include "supertrees.h"
#include <bits/stdc++.h>
using namespace std;


struct DSU {
    vector<int> parent;
    vector<int> size;

    DSU(int n) {
        parent.resize(n);
        iota(parent.begin(), parent.end(), 0);
        size.assign(n, 1);
    }

    int find(int v) {
        if (parent[v] == v) {
            return v;
        } else {
            return parent[v] = find(parent[v]);
        }
    }

    void unite(int u, int v) {
        if (u == v) return;
        u = find(u);
        v = find(v);
        if (size[u] > size[v]) swap(u, v);
        parent[u] = v;
        size[v] += size[u];
    }
};


int construct(vector<vector<int>> p) {
	int n = p.size();

	vector<vector<int>> g(n, vector<int>(n));

    // 1) must be transitive:
    // p[u][w] * p[w][v] = p[v][w] * p[w][u] = p[u][v] = p[v][u], for any u, v, w
    bool ok = true;
    DSU dsu(n);
    for (int u = 0; u < n; ++u) {
        if (p[u][u] == 2) {
            ok = false;
        }
        for (int v = u + 1; v < n; ++v) {
            if (p[u][v] > 0) {
                dsu.unite(u, v);
            }
        }
    }
    map<int, vector<int>> comps;
    for (int v = 0; v < n; ++v) {
        comps[dsu.find(v)].push_back(v);
    }
    
    for (const auto& [c, comp] : comps) {
        bool has_two = false;
        for (auto u : comp) {
            for (auto v : comp) {
                if (p[u][v] == 0) {
                    ok = false;
                    break;
                }
                if (p[u][v] == 2) {
                    has_two = true;
                }
            }
        }
        for (int i = 0; i < (int)comp.size() - 1; ++i) {
            g[comp[i]][comp[i + 1]] = g[comp[i + 1]][comp[i]] = 1;
        }
        if (has_two) {
            g[comp[0]][comp.back()] = g[comp.back()][comp[0]] = 1;
        }
    }

	if (ok) {
        build(g);
        return 1;
    }
    return 0;
}

• Subtask 1: 11 / 11
• Subtask 2: 10 / 10
• Subtask 3: 0 / 19
• Subtask 4: 0 / 35
• Subtask 5: 0 / 21
• Subtask 6: 0 / 4