This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#define For(i, a, b) for(int i = a; i <= b; i++)
#define Forr(i, a, b) for(int i = a; i >= b; i--)
#define F first
#define S second
#define all(x) x.begin(), x.end()
#define sz(x) ((int)x.size())
#define eb emplace_back
#define int LL
using namespace std;
using LL = long long;
using pii = pair<int, int>;
struct Frac {
int x, y;
Frac(int _x = 0, int _y = 1) {
x = _x; y = _y;
simp();
}
void simp() {
int g = __gcd(x, y);
x /= g; y /= g;
}
};
Frac operator-(const Frac &a) {
return Frac(-a.x, a.y);
}
Frac operator+(const Frac &a, const Frac &b) {
return Frac(a.x * b.y + a.y * b.x, a.y * b.y);
}
Frac operator-(const Frac &a, const Frac &b) {
return a + (-b);
}
Frac operator*(const Frac &a, const Frac &b) {
return Frac(a.x * b.x, a.y * b.y);
}
Frac operator/(const Frac &a, const Frac &b) {
return Frac(a.x * b.y, a.y * b.x);
}
bool operator==(const Frac &a, const Frac &b) {
return a.x * b.y == a.y * b.x;
}
bool operator<(const Frac &a, const Frac &b) {
return a.x * b.y < a.y * b.x;
}
bool operator>(const Frac &a, const Frac &b) {
return b < a;
}
bool operator<=(const Frac &a, const Frac &b) {
return a < b || a == b;
}
bool operator>=(const Frac &a, const Frac &b) {
return a > b || a == b;
}
const int MAXN = 2010;
int v[MAXN][MAXN];
Frac tar[MAXN];
int ids[MAXN];
Frac rem[MAXN];
Frac x[MAXN];
bool check(int n, int l) {
For(i, 1, l) rem[i] = Frac(1);
int pos = 1;
For(it, 1, n) {
int id = ids[it];
Frac now(0);
while(now + rem[pos] * v[id][pos] < tar[id]) {
if(pos == l) return false;
now = now + rem[pos] * v[id][pos];
pos++;
}
Frac owo = (tar[id] - now) / v[id][pos];
assert(owo <= 1);
rem[pos] = rem[pos] - owo;
x[it] = pos - rem[pos];
}
return true;
}
int32_t main() {
ios::sync_with_stdio(false);
cin.tie(0);
// nyanyanyanyanya
int n, l; cin >> n >> l;
assert(n <= 6);
For(i, 1, n) {
tar[i] = Frac();
For(j, 1, l) {
cin >> v[i][j];
tar[i].x += v[i][j];
}
tar[i] = tar[i] / n;
}
For(i, 1, n) ids[i] = i;
do {
if(check(n, l)) {
For(i, 1, n - 1) cout << x[i].x << " " << x[i].y << "\n";
For(i, 1, n) cout << ids[i] << " \n"[i == n];
return 0;
}
} while(next_permutation(ids + 1, ids + n + 1));
assert(false);
return 0;
}
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