제출 #701322

#제출 시각아이디문제언어결과실행 시간메모리
701322n1kCatfish Farm (IOI22_fish)C++17
0 / 100
1057 ms2097152 KiB
#include <bits/stdc++.h> #define ll long long #define vt vector #define pb push_back #define ar array #define all(x) (x).begin(), (x).end() #define sz(x) (x).size() using namespace std; /* ## TAKE IT EASY ## 1. simplify 2. add new elements 3. brute force solution 4. optimize 5. start implementing */ // --- templates --- // --- code --- const int N = 300 + 5; ll dp[N][2][N]; ll max_weights(int n, int m, vt<int> X, vt<int> Y, vt<int> W){ memset(dp, 0, sizeof dp); int h = n + 5; vt<vt<ll>> a(n + 5, vt<ll>(h)); for(int i = 0; i < m; i++){ a[X[i]][Y[i] + 1] = W[i]; } for(int i = 0; i < n; i++){ for(int j = 1; j < h; j++){ a[i][j] += a[i][j - 1]; } } for(int i = 0; i < n; i++){ for(int flow = 0; flow < 2; flow++){ for(int h1 = 0; h1 < h; h1++){ for(int h2 = 0; h2 < (flow ? h : h1 + 1); h2++){ int nflow = h1 <= h2; ll l = 0, r = a[i + 1][h2], sub = a[i][min(h1, h2)]; if(i == 0){ dp[i][nflow][h2] = max(dp[i][nflow][h2], r); }else{ l = max((ll)0, a[i - 1][h2] - a[i - 1][h1]); dp[i][nflow][h2] = max(dp[i][nflow][h2], l + dp[i - 1][flow][h1] + r - sub); } } } } } ll ans = 0; for(int flow = 0; flow < 2; flow++){ for(int h1 = 0; h1 < h; h1++){ ans = max(ans, dp[n - 1][flow][h1]); } } return ans; }
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