Submission #699874

#	Time	Username	Problem	Language	Result	Execution time	Memory
699874		bdl	Sushi (JOI16_sushi)	C++17	100 / 100	1950 ms	77692 KiB

sushi

/*
> Statement

You are given a circular array A of length N. You are given Q queries, each giving (l, r, a). You are to run the following code:

for (int i = l; i <= r; i++)
  if (a < A[i])
    swap(a, A[i]);

For each query, output the final value of a.

> Scoring

05: 1 <= N, Q <= 2e3
15: For all queries, l = r = 1
80: 1 <= N <= 4e5, 1 <= Q <= 2.5e4, 1 <= A_i <= 1e9
*/

#include <iostream>
#include <queue>
#include <vector>
using namespace std;

const int N = 4e5, B = 633;

struct T {
  int *a, n;
  vector<int> u;
  priority_queue<int> v;

  void build(int *a_, int n_) {
    a = a_, n = n_;
    pull();
  }
  void pull() {
    v = priority_queue<int>(a, a + n);
  }
  int force(int l, int r, int x) {
    for (int i = l; i <= r; i++)
      if (x < a[i])
        swap(x, a[i]);
    return x;
  }
  int put(int x) {
    int t = v.top();
    if (x < t) {
      v.pop();
      v.push(x);
      u.push_back(x);
      x = t;
    }
    return x;
  }
  void push() {
    if (u.empty())
      return;
    static priority_queue<int, vector<int>, greater<int>> u_;
    u_ = priority_queue<int, vector<int>, greater<int>>(u.begin(), u.end());
    int t = u_.top();
    for (int i = 0; i < n; i++)
      if (t < a[i]) {
        u_.pop(), u_.push(a[i]);
        a[i] = t, t = u_.top();
      }
    u.clear();
  }
} b[(N - 1) / B + 1];

int update(int l, int r, int x) {
  if (l / B == r / B) {
    b[l / B].push();
    x = b[l / B].force(l - l / B * B, r - l / B * B, x);
    b[l / B].pull();
  } else {
    b[l / B].push();
    x = b[l / B].force(l - l / B * B, b[l / B].n - 1, x);
    b[l / B].pull();
    for (int i = l / B + 1; i < r / B; i++)
      x = b[i].put(x);
    b[r / B].push();
    x = b[r / B].force(0, r - r / B * B, x);
    b[r / B].pull();
  }
  return x;
}

int main() {
  ios::sync_with_stdio(false);
  cin.tie(NULL);
  int n, q;
  cin >> n >> q;
  static int a[N];
  for (int i = 0; i < n; i++)
    cin >> a[i];
  for (int i = 0; i <= (n - 1) / B; i++)
    b[i].build(a + B * i, min(n, B * (i + 1)) - B * i);
  while (q--) {
    int l, r, x;
    cin >> l >> r >> x, l--, r--;
    if (l <= r)
      x = update(l, r, x);
    else {
      swap(l, r);
      x = update(r, n - 1, x);
      x = update(0, l, x);
    }
    cout << x << '\n';
  }
  return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 15 / 15
• Subtask 3: 80 / 80