oj.uz

답안 #69408

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
69408 2018-08-20T19:09:22 Z Benq Dragon 2 (JOI17_dragon2) C++14
60 / 100
 4000 ms 20040 KB 
#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")
 
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/rope>
 
using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
 
typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;
 
typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
 
template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;
 
#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)
 
#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
 
const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 30001;
 
namespace geo {
    template<class T> istream& operator>> (istream& is, complex<T>& p) {
        T value;
        is >> value; p.real(value);
        is >> value; p.imag(value);
        return is;
    }
    void nor(pd& x) { if (x.f < -M_PIl) x.f += 2*M_PIl, x.s += 2*M_PIl; }
    ld area(cd a, cd b, cd c) { return (conj(b-a)*(c-a)).imag(); }
}
 
using namespace geo;
 
struct BIT {
    vector<array<ld,3>> toUpd;
    vector<pair<array<ld,3>,int*>> toQuery;
    vd m;
    vi bit;
    
    void clr() {
        toUpd.clear(), toQuery.clear(), m.clear(), bit.clear();
    }
    
    void upd(ld x, int y) {
        for (int X = ub(all(m),x)-m.begin()-1; X < sz(bit); X += (X&-X))
            bit[X] += y;
    }
    
    void query(ld x, int y, int* z) {
        for (int X = ub(all(m),x)-m.begin()-1; X; X -= (X&-X)) 
            (*z) += y*bit[X];
    }
    
    void prop() {
        for (auto x: toUpd) m.pb(x[1]);
        m.pb(-MOD); sort(all(m)); m.erase(unique(all(m)),m.end());
        bit.resize(sz(m));
        sort(all(toUpd)), sort(all(toQuery));
        
        int ind = 0;
        for (auto x: toQuery) {
            while (ind < sz(toUpd) && toUpd[ind][0] <= x.f[0]) {
                upd(toUpd[ind][1],toUpd[ind][2]);
                ind ++;
            } 
            query(x.f[1],x.f[2],x.s);
        }
    }
};
 
int N,M,group[MX],ans[100001];
vi member[MX];
cd pos[MX], h[2];
pd POS[MX];
pair<pd,pd> BOUND[MX];
vpi query[MX], query2[MX];
BIT z;
 
void process1(int x) {
    z.clr();
    array<int,MX> co; co.fill(0);
    for (int a: member[x]) {
        z.toUpd.pb({BOUND[a].f.f,BOUND[a].s.f,1});
        z.toUpd.pb({BOUND[a].f.s,BOUND[a].s.s,1});
        z.toUpd.pb({BOUND[a].f.f,BOUND[a].s.s,-1});
        z.toUpd.pb({BOUND[a].f.s,BOUND[a].s.f,-1});
    }
    FOR(a,1,N+1) {
        z.toQuery.pb({{POS[a].f,POS[a].s,1},&co[group[a]]});
        z.toQuery.pb({{POS[a].f+2*M_PIl,POS[a].s,1},&co[group[a]]});
        z.toQuery.pb({{POS[a].f,POS[a].s+2*M_PIl,1},&co[group[a]]});
        z.toQuery.pb({{POS[a].f+2*M_PIl,POS[a].s+2*M_PIl,1},&co[group[a]]});
    }
    z.prop(); 
    for (auto a: query[x]) ans[a.s] = co[a.f]; 
}
 
void process2(int x) {
    for (auto a: query[x]) query2[a.f].pb({x,a.s}); 
}
 
void process(int x) {
    if (sz(member[x]) >= 300) process1(x);
    else process2(x);
}
 
int get() {
    int z = 1e9;
    return rand() % (2*z+1)-z;
}
 
cd gen() { return {get(),get()}; }
 
void input() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> N >> M;
    FOR(i,1,N+1) {
        //pos[i] = gen();
        //group[i] = rand() % M+1;
        cin >> pos[i] >> group[i];
        member[group[i]].pb(i);
    }
    //h[0] = gen();
    //h[1] = gen();
    F0R(i,2) cin >> h[i];
    FOR(i,1,N+1) {
        POS[i].f = arg(pos[i]-h[0]);
        POS[i].s = arg(pos[i]-h[1]);
        if (area(h[0],h[1],pos[i]) > 0) BOUND[i] = {{POS[i].f-M_PIl,POS[i].f},{POS[i].s,POS[i].s+M_PIl}};
        else BOUND[i] = {{POS[i].f,POS[i].f+M_PIl},{POS[i].s-M_PIl,POS[i].s}};
        nor(BOUND[i].f); nor(BOUND[i].s);
    }
}
 
int main() {
    input();
    int Q; cin >> Q;
    F0R(i,Q) {
        int f,g; cin >> f >> g;
        // int f = rand() % M+1, g = rand() % M+1;
        query[f].pb({g,i});
    }
    FOR(i,1,M+1) process(i);
    int tmp = 0;
    FOR(i,1,M+1) {
        z.clr();
        for (auto a: query2[i]) for (int b: member[a.f]) {
            z.toQuery.pb({{BOUND[b].f.s,BOUND[b].s.s,1},&ans[a.s]});
            z.toQuery.pb({{BOUND[b].f.f,BOUND[b].s.s,-1},&ans[a.s]});
            z.toQuery.pb({{BOUND[b].f.s,BOUND[b].s.f,-1},&ans[a.s]});
            z.toQuery.pb({{BOUND[b].f.f,BOUND[b].s.f,1},&ans[a.s]});
        }
        for (int a: member[i]) {
            z.toUpd.pb({POS[a].f,POS[a].s,1});
            z.toUpd.pb({POS[a].f+2*M_PIl,POS[a].s,1});
            z.toUpd.pb({POS[a].f,POS[a].s+2*M_PIl,1});
            z.toUpd.pb({POS[a].f+2*M_PIl,POS[a].s+2*M_PIl,1});
        }
        tmp += sz(z.toQuery);
        z.prop();
    }
    // cout << tmp << "\n";
    F0R(i,Q) cout << ans[i] << "\n";
}
 
/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
* if you have no idea just guess the appropriate well-known algo instead of doing nothing :/
*/

Compilation message

dragon2.cpp: In function 'cd gen()':
dragon2.cpp:139:23: warning: narrowing conversion of 'get()' from 'int' to 'long double' inside { } [-Wnarrowing]
 cd gen() { return {get(),get()}; }
                    ~~~^~
dragon2.cpp:139:29: warning: narrowing conversion of 'get()' from 'int' to 'long double' inside { } [-Wnarrowing]
 cd gen() { return {get(),get()}; }
                          ~~~^~

Subtask #1
15.0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 29 ms 4592 KB Output is correct
2 Correct 44 ms 4592 KB Output is correct
3 Correct 179 ms 4592 KB Output is correct
4 Correct 359 ms 6140 KB Output is correct
5 Correct 132 ms 6448 KB Output is correct
6 Correct 10 ms 6448 KB Output is correct
7 Correct 11 ms 6448 KB Output is correct
8 Correct 25 ms 6448 KB Output is correct
9 Correct 22 ms 6448 KB Output is correct
10 Correct 22 ms 6448 KB Output is correct

Subtask #2
45.0 / 45.0

# 결과 실행 시간 메모리 Grader output
1 Correct 270 ms 20016 KB Output is correct
2 Correct 674 ms 20016 KB Output is correct
3 Correct 2403 ms 20016 KB Output is correct
4 Correct 86 ms 20016 KB Output is correct
5 Correct 67 ms 20016 KB Output is correct
6 Correct 249 ms 20016 KB Output is correct
7 Correct 247 ms 20016 KB Output is correct
8 Correct 263 ms 20016 KB Output is correct
9 Correct 229 ms 20016 KB Output is correct
10 Correct 196 ms 20016 KB Output is correct

Subtask #3
0 / 40.0

# 결과 실행 시간 메모리 Grader output
1 Correct 29 ms 4592 KB Output is correct
2 Correct 44 ms 4592 KB Output is correct
3 Correct 179 ms 4592 KB Output is correct
4 Correct 359 ms 6140 KB Output is correct
5 Correct 132 ms 6448 KB Output is correct
6 Correct 10 ms 6448 KB Output is correct
7 Correct 11 ms 6448 KB Output is correct
8 Correct 25 ms 6448 KB Output is correct
9 Correct 22 ms 6448 KB Output is correct
10 Correct 22 ms 6448 KB Output is correct
11 Correct 270 ms 20016 KB Output is correct
12 Correct 674 ms 20016 KB Output is correct
13 Correct 2403 ms 20016 KB Output is correct
14 Correct 86 ms 20016 KB Output is correct
15 Correct 67 ms 20016 KB Output is correct
16 Correct 249 ms 20016 KB Output is correct
17 Correct 247 ms 20016 KB Output is correct
18 Correct 263 ms 20016 KB Output is correct
19 Correct 229 ms 20016 KB Output is correct
20 Correct 196 ms 20016 KB Output is correct
21 Correct 298 ms 20040 KB Output is correct
22 Correct 703 ms 20040 KB Output is correct
23 Correct 3526 ms 20040 KB Output is correct
24 Execution timed out 4011 ms 20040 KB Time limit exceeded
25 Halted 0 ms 0 KB -