제출 #69407

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
69407		Benq	Dragon 2 (JOI17_dragon2)	C++14	15 / 100	4027 ms	19996 KiB

dragon2

#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")
 
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/rope>
 
using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;
 
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;
 
typedef pair<int, int> pi;
typedef pair<ll,ll> pl;
typedef pair<ld,ld> pd;
 
typedef vector<int> vi;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<pi> vpi;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
 
template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>;
 
#define FOR(i, a, b) for (int i=a; i<(b); i++)
#define F0R(i, a) for (int i=0; i<(a); i++)
#define FORd(i,a,b) for (int i = (b)-1; i >= a; i--)
#define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--)
 
#define sz(x) (int)(x).size()
#define mp make_pair
#define pb push_back
#define f first
#define s second
#define lb lower_bound
#define ub upper_bound
#define all(x) x.begin(), x.end()
 
const int MOD = 1000000007;
const ll INF = 1e18;
const int MX = 30001;
 
namespace geo {
    template<class T> istream& operator>> (istream& is, complex<T>& p) {
        T value;
        is >> value; p.real(value);
        is >> value; p.imag(value);
        return is;
    }
    void nor(pd& x) { if (x.f < -M_PIl) x.f += 2*M_PIl, x.s += 2*M_PIl; }
    ld area(cd a, cd b, cd c) { return (conj(b-a)*(c-a)).imag(); }
}
 
using namespace geo;
 
struct BIT {
    vector<array<ld,3>> toUpd;
    vector<pair<array<ld,3>,int*>> toQuery;
    vd m;
    vi bit;
    
    void clr() {
        toUpd.clear(), toQuery.clear(), m.clear(), bit.clear();
    }
    
    void upd(ld x, int y) {
        for (int X = ub(all(m),x)-m.begin()-1; X < sz(bit); X += (X&-X))
            bit[X] += y;
    }
    
    void query(ld x, int y, int* z) {
        for (int X = ub(all(m),x)-m.begin()-1; X; X -= (X&-X)) 
            (*z) += y*bit[X];
    }
    
    void prop() {
        for (auto x: toUpd) m.pb(x[1]);
        m.pb(-MOD); sort(all(m)); m.erase(unique(all(m)),m.end());
        bit.resize(sz(m));
        sort(all(toUpd)), sort(all(toQuery));
        
        int ind = 0;
        for (auto x: toQuery) {
            while (ind < sz(toUpd) && toUpd[ind][0] <= x.f[0]) {
                upd(toUpd[ind][1],toUpd[ind][2]);
                ind ++;
            } 
            query(x.f[1],x.f[2],x.s);
        }
    }
};
 
int N,M,group[MX],ans[100001];
vi member[MX];
cd pos[MX], h[2];
pd POS[MX];
pair<pd,pd> BOUND[MX];
vpi query[MX], query2[MX];
BIT z;
 
void process1(int x) {
    z.clr();
    array<int,MX> co; co.fill(0);
    for (int a: member[x]) {
        z.toUpd.pb({BOUND[a].f.f,BOUND[a].s.f,1});
        z.toUpd.pb({BOUND[a].f.s,BOUND[a].s.s,1});
        z.toUpd.pb({BOUND[a].f.f,BOUND[a].s.s,-1});
        z.toUpd.pb({BOUND[a].f.s,BOUND[a].s.f,-1});
    }
    FOR(a,1,N+1) {
        z.toQuery.pb({{POS[a].f,POS[a].s,1},&co[group[a]]});
        z.toQuery.pb({{POS[a].f+2*M_PIl,POS[a].s,1},&co[group[a]]});
        z.toQuery.pb({{POS[a].f,POS[a].s+2*M_PIl,1},&co[group[a]]});
        z.toQuery.pb({{POS[a].f+2*M_PIl,POS[a].s+2*M_PIl,1},&co[group[a]]});
    }
    z.prop(); 
    for (auto a: query[x]) ans[a.s] = co[a.f]; 
}
 
void process2(int x) {
    for (auto a: query[x]) query2[a.f].pb({x,a.s}); 
}
 
void process(int x) {
    if (sz(member[x]) >= 150) process1(x);
    else process2(x);
}
 
int get() {
    int z = 1e9;
    return rand() % (2*z+1)-z;
}
 
cd gen() { return {get(),get()}; }
 
void input() {
    ios_base::sync_with_stdio(0); cin.tie(0);
    cin >> N >> M;
    FOR(i,1,N+1) {
        //pos[i] = gen();
        //group[i] = rand() % M+1;
        cin >> pos[i] >> group[i];
        member[group[i]].pb(i);
    }
    //h[0] = gen();
    //h[1] = gen();
    F0R(i,2) cin >> h[i];
    FOR(i,1,N+1) {
        POS[i].f = arg(pos[i]-h[0]);
        POS[i].s = arg(pos[i]-h[1]);
        if (area(h[0],h[1],pos[i]) > 0) BOUND[i] = {{POS[i].f-M_PIl,POS[i].f},{POS[i].s,POS[i].s+M_PIl}};
        else BOUND[i] = {{POS[i].f,POS[i].f+M_PIl},{POS[i].s-M_PIl,POS[i].s}};
        nor(BOUND[i].f); nor(BOUND[i].s);
    }
}
 
int main() {
    input();
    int Q; cin >> Q;
    F0R(i,Q) {
        int f,g; cin >> f >> g;
        // int f = rand() % M+1, g = rand() % M+1;
        query[f].pb({g,i});
    }
    FOR(i,1,M+1) process(i);
    int tmp = 0;
    FOR(i,1,M+1) {
        z.clr();
        for (auto a: query2[i]) for (int b: member[a.f]) {
            z.toQuery.pb({{BOUND[b].f.s,BOUND[b].s.s,1},&ans[a.s]});
            z.toQuery.pb({{BOUND[b].f.f,BOUND[b].s.s,-1},&ans[a.s]});
            z.toQuery.pb({{BOUND[b].f.s,BOUND[b].s.f,-1},&ans[a.s]});
            z.toQuery.pb({{BOUND[b].f.f,BOUND[b].s.f,1},&ans[a.s]});
        }
        for (int a: member[i]) {
            z.toUpd.pb({POS[a].f,POS[a].s,1});
            z.toUpd.pb({POS[a].f+2*M_PIl,POS[a].s,1});
            z.toUpd.pb({POS[a].f,POS[a].s+2*M_PIl,1});
            z.toUpd.pb({POS[a].f+2*M_PIl,POS[a].s+2*M_PIl,1});
        }
        tmp += sz(z.toQuery);
        z.prop();
    }
    // cout << tmp << "\n";
    F0R(i,Q) cout << ans[i] << "\n";
}
 
/* Look for:
* the exact constraints (multiple sets are too slow for n=10^6 :( ) 
* special cases (n=1?)
* overflow (ll vs int?)
* array bounds
* if you have no idea just guess the appropriate well-known algo instead of doing nothing :/
*/

컴파일 시 표준 에러 (stderr) 메시지

dragon2.cpp: In function 'cd gen()':
dragon2.cpp:139:23: warning: narrowing conversion of 'get()' from 'int' to 'long double' inside { } [-Wnarrowing]
 cd gen() { return {get(),get()}; }
                    ~~~^~
dragon2.cpp:139:29: warning: narrowing conversion of 'get()' from 'int' to 'long double' inside { } [-Wnarrowing]
 cd gen() { return {get(),get()}; }
                          ~~~^~

• Subtask 1: 15 / 15
• Subtask 2: 0 / 45
• Subtask 3: 0 / 40