이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
ll MOD = 998244353;
int main() {
ll n, m;
cin >> n >> m;
vector<vector<ll> > adj(n);
vector<vector<ll> > adj2(n);
for (ll i = 0; i < m; i++) {
ll a, b;
cin >> a >> b;
a--;b--;
adj[a].push_back(b);
adj2[a].push_back(b);
adj2[b].push_back(a);
}
vector<pair<ll, ll> > dp(1<<n, {0, 0});
dp[0]={1, 0};
for (ll i = 0; i < n; i++) dp[(1 << i)] = {1, 0};
for (ll i = 1; i < (1<<n); i++) {
// cout << i << dp[i].first << dp[i].second << endl;
for (ll ne = 0; ne < n; ne++) {
if ((1 << ne) & i) continue;
ll c = 0;
for (auto val: adj[ne]) {
if ((1 << val) & i) {
c++;
}
}
bool conn = false;
for (auto val: adj2[ne]) if ((1<<val)&i)conn=true;
// cout << (i^(1 << ne)) << dp[i].first << c << endl;
if (!conn)continue;
dp[i^(1 << ne)].second=((dp[i^(1 << ne)].second)%MOD+((dp[i].second)%MOD)+(dp[i].first*c)%MOD)%MOD;
dp[i^(1 << ne)].first=(dp[i^(1 << ne)].first+dp[i].first)%MOD;
// cout << i<<(ne) << dp[i^(1 << ne)].second << endl;
}
// cout << dp[]
}
ll ans = 1;
vector<bool> v(n, false);
for (int i = 0; i < n; i++) {
if (!v[i]) {
ll current=0;
v[i] = true;
queue<ll> q;
q.push(i);
while (!q.empty()) {
ll cur = q.front();
q.pop();
current|=(1<<cur);
for (auto val: adj2[cur]) if (!v[val]) {
q.push(val);v[val]=true;
}
}
ans = (ans * dp[current].second)%MOD;
}
}
cout << ans << endl;
}
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