# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
690294 | moonhero | Luxury burrow (IZhO13_burrow) | C++14 | 1889 ms | 12476 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const int N = 1e3 + 5;
int a[N][N], x[N][N], n, m, nd, ps[N][N];
bool c (int ar, int l, int r) {
// cout << ar << '\n';
for (int i = 1; i <= sqrt(ar); i++) {
int k = l + i - 1, j = r + (ar / i) - 1;
if (k <= n && j <= m) {
int sum = ps[k][j] - ps[l - 1][j] - ps[k][r - 1] + ps[l - 1][r - 1];
// cout << l << ' ' << r << ' ' << k << ' ' << j << ' ' << sum << '\n';
if (sum == ar) return 1;
}
} for (int i = 1; i <= sqrt(ar); i++) {
int k = l + (ar / i) - 1, j = r + i - 1;
if (k <= n && j <= m) {
int sum = ps[k][j] - ps[l - 1][j] - ps[k][r - 1] + ps[l - 1][r - 1];
// cout << l << ' ' << r << ' ' << k << ' ' << j << ' ' << sum << '\n';
if (sum == ar) return 1;
}
} return 0;
}
int check (int d) {
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
if (a[i][j] >= d) x[i][j] = 1;
else x[i][j] = 0;
ps[i][j] = ps[i - 1][j] + ps[i][j - 1] - ps[i - 1][j - 1] + x[i][j];
}
}
int ans = 0;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= m; j++) {
for (int k = i; k <= n; k++) {
int l = j, r = m, res = 0;
while (l <= r) {
int md = (l + r) / 2;
int ar = (md - j + 1) * (k - i + 1);
int sum = ps[k][md] - ps[i - 1][md] - ps[k][j - 1] + ps[i - 1][j - 1];
if (sum == ar) l = md + 1, res = md;
else r = md - 1;
}
res = (res - j + 1) * (k - i + 1);
if (res >= nd) {
ans = max(ans, res);
}
}
}
} return ans;
}
int main () {
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
cin >> n >> m >> nd;
if (n > 200 || m > 200) abort();
int mx = 0;
for (int i = 0; i < N; i++)
for (int j = 0; j < N; j++)
a[i][j] = 0, x[i][j] = 0, ps[i][j] = 0;
for (int i = 1; i <= n; i++)
for (int j = 1; j <= m; j++) {
cin >> a[i][j];
mx = max(mx, a[i][j]);
}
int l = 0, r = mx, res = 0, ans = 0;
while (l <= r) {
int md = (l + r) / 2;
// cout << md << '\n';
if (check(md) > 0) l = md + 1, res = md, ans = check(md);
else r = md - 1;
} cout << res << ' ' << ans << '\n';
return 0;
}
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---|---|---|---|---|
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