이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pi = pair<int, int>;
using pl = pair<long long, long long>;
using vi = vector<int>;
using vl = vector<long long>;
using vpi = vector<pair<int, int>>;
using vpl = vector<pair<long long, long long>>;
#define fur(i, a, b) for(ll i = a; i <= (ll)b; ++i)
#define ruf(i, a, b) for(ll i = a; i >= (ll)b; --i)
#define fr first
#define sc second
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define nl "\n"
#define all(x) (x).begin(),(x).end()
#define rall(x) (x).rbegin(),(x).rend()
const ll inf = 1e18L;
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
ll n;
cin >> n;
ll t[n + 1];
fur(i, 1, n) {
cin >> t[i];
}
cout << n * t[1] << nl;
return 0;
ll dp[n + 1][n + 1];
fur(i, 0, n) {
fur(j, 0, n) {
dp[i][j] = inf;
}
}
fur(i, 1, n) {
dp[i][0] = t[i] * i;
}
fur(j, 1, n - 1) {
fur(i, 1, n) {
dp[i][j] = dp[i - 1][j];
}
}
if(n == 1) {
cout << t[1] << nl;
}
else if(n == 2) {
cout << min(2*max(t[1], t[2]), 2*t[1] + t[2]) << nl;
}
if(n == 3) {
ll ans = inf;
// 00
ans = min(ans, 3*max({t[1],t[2],t[3]}));
//01
ans = min(ans, 3*max(t[1], t[2]) + t[3]);
// 10
ans = min(ans, 3*t[1] + 2*max(t[2], t[3]));
// 11
ans = min(ans, 3*t[1] + 2*t[2] + t[3]);
cout << ans << nl;
}
}
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |
# | Verdict | Execution time | Memory | Grader output |
---|
Fetching results... |