제출 #688424

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
688424		stanislavpolyn	Necklace (Subtask 1-3) (BOI19_necklace1)	C++17	5 / 85	1562 ms	332 KiB

necklace

#include <bits/stdc++.h>

#define fr(i, a, b) for (int i = (a); i <= (b); ++i)
#define rf(i, a, b) for (int i = (a); i >= (b); --i)
#define fe(x, y) for (auto& x : y)

#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define mt make_tuple

#define all(x) (x).begin(), (x).end()
#define pw(x) (1LL << (x))
#define sz(x) (int)(x).size()

using namespace std;

mt19937_64 rng(228);

#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template <typename T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define fbo find_by_order
#define ook order_of_key

template <typename T>
bool umn(T& a, T b) {
    return a > b ? a = b, 1 : 0;
}
template <typename T>
bool umx(T& a, T b) {
    return a < b ? a = b, 1 : 0;
}

using ll = long long;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
template <typename T>
using ve = vector<T>;

const int M = 3005 * 3005;

string a, b;

ve<int> ord;

bool ask(string s, bool print = 0) {
    fr (i, 0, sz(b) - sz(s)) {
        if (b.substr(i, sz(s)) == s) {
            if (print) {
                cout << i << "\n";
            }
            return 1;
        }
    }
    return 0;
}

bool possible(int len, bool print = 0) {
    fr (i, 0, sz(a) - len) {
        fr (shift, 0, len - 1){
            string s = a.substr(i + shift, len - shift) + a.substr(i, shift);

            if (ask(s)) {
                if (print) {
                    cout << i << " ";
                    ask(s, 1);
                }

                return 1;
            }
            reverse(all(s));
            if (ask(s)) {
                if (print) {
                    cout << i << " ";
                    ask(s, 1);
                }

                return 1;
            }
        }
    }
    return 0;
}

int main() {
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#else
    ios::sync_with_stdio(0);
    cin.tie(0);
#endif

    cin >> a >> b;

    {
        fr (i, 0, sz(b) - 1) {
            ord.pb(i);
        }
        sort(all(ord), [](int i, int j) {
            while (i < sz(b) && j < sz(b) && b[i] == b[j]) {
                i++;
                j++;
            }
            if (i == sz(b) && j < sz(b)) {
                return 1;
            }
            if (i < sz(b) && j < sz(b) && b[i] < b[j]) {
                return 1;
            }
            return 0;
        });
    }

    int l = 0;
    int r = min(sz(a), sz(b));
    while (l < r) {
        int mid = l + ((r - l + 1) >> 1);

        if (possible(mid)) {
            l = mid;
        } else {
            r = mid - 1;
        }
    }

    cout << l << "\n";

    possible(l, 1);

    return 0;
}

• Subtask 1: 5 / 25
• Subtask 2: 0 / 20
• Subtask 3: 0 / 40