이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
/** made by amunduzbaev **/
#include <bits/stdc++.h>
using namespace std;
//#pragma GCC target ("avx2")
//#pragma GCC optimization ("O3")
//#pragma GCC optimization ("unroll-loops")
#define ff first
#define ss second
#define pb push_back
#define mp make_pair
#define ub upper_bound
#define lb lower_bound
#define sz(x) (int)x.size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(),x.rend()
#define NeedForSpeed ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define vv vector
#define int long long
typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef vector<int> vii;
typedef vector<pll> vpll;
typedef vector<pii> vpii;
typedef pair<int, pii> ipii;
typedef pair<pii, int> piii;
template<class T> bool umin(T& a, const T& b) {return a > b? a = b, true:false;}
template<class T> bool umax(T& a, const T& b) {return a < b? a = b, true:false;}
const int N = 2e5+5;
const int mod = 1e9+7;
const ll inf = 1e18;
const ld Pi = acos(-1);
#define MULTI 0
int n, m, k, ans, res, a[N];
inline bool check(int s){
int l = 0, r = m-1, res = 0;
while(l < r){
if(a[l] + a[r] == s) { res+=2, l++, r--; continue; }
if(a[l] + a[r] > s) r--;
else l++;
}
//cout<<s<<" "<<res<<"\n";
if(res >= n){
vii tt;
int l = 0, r = m-1;
while(l < r){
if(a[l] + a[r] == s) { tt.pb(a[l]), tt.pb(a[r]), l++, r--; }
else if(a[l] + a[r] > s) r--;
else l++;
if(sz(tt) >= n) break;
}
sort(all(tt));
for(auto x:tt) cout<<x<<" ";
cout<<"\n";
return 1;
}
return 0;
}
inline int rd(){
char r;
int start = 0, ret=0;
while(true){
r=getchar();
if((r-'0'<0 || r-'0'>9) && r!='-' && !start) continue;
if((r-'0'<0 || r-'0'>9) && r!='-' && start) break;
if(start)ret*=10;
start=true;
ret+=r-'0';
} return ret;
}
inline void solve(int t_case){
srand(time(NULL));
n = rd(), k = rd();
m = n+k;
for(int i=0;i<m;i++) a[i] = rd();
sort(a, a+m);
if(n >= 18000 && k >= 15){
for(int j=0;j<3;j++){
int i = rand()%m;
int ri = m-i-1;
if(check(a[i] + a[ri])) return;
for(int j=1;j<k;j++){
if(check(a[i] + a[ri-j])) return;
if(check(a[i] + a[ri+j])) return;
}
}
} else {
map<int, int> mm;
for(int i=0;i<=k;i++){
for(int j=1;j<=k-i+1;j++){
if(mm[a[i] + a[m-j]]) continue;
mm[a[i] + a[m-j]] = 1;
if(check(a[i] + a[m-j])) return;
}
}
}
}
signed main(){
NeedForSpeed
if(!MULTI) {
solve(1);
} else {
int t; cin>>t;
for(int t_case = 1; t_case <= t; t_case++) solve(t_case);
}
return 0;
}
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