이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define all(a) a.begin(),a.end()
#define pb push_back
#define vt vector
#define endl '\n'
#define Y second
#define X first
typedef long long ll;
typedef long double ld;
const ll mod=1e9+7;
const ll INF=1e18;
const int inf=1e9;
const int N=2e6+505;
const int M=3e3+10;
const int dx[]={0,0,1,-1};
const int dy[]={1,-1,0,0};
/*From Benq:
stuff you should look for
* int overflow, array bounds
* special cases (n=1?)
* do smth instead of nothing and stay organized
* WRITE STUFF DOWN
* DON'T GET STUCK ON ONE APPROACH*/
int n,a[N],k[N];
int dp[N],pr[N],pos[N];
void solve(){
cin>>n;
for(int i=0; i<=256; ++i){
pos[i]=-1;
pr[i]=-1;
}
for(int i=1; i<=n; ++i){
cin>>a[i];
dp[i]=1;
}for(int i=1; i<=n; ++i)cin>>k[i];
int ans=1,r=1;
for(int i=1; i<=n; ++i){
for(int x=0; x<=256; ++x){
if(__builtin_popcount(a[i]&x)==k[i] && pos[x]!=-1){
int ps=pos[x];
dp[i]=max(dp[i],dp[ps]+1);
if(dp[i]==dp[ps]+1)pr[i]=ps;
ans=max(ans,dp[i]);
if(ans==dp[i])r=i;
}
}pos[a[i]]=i;
}cout<<ans<<endl;
vt<int>lst;
while(r!=-1){
lst.pb(r);
r=pr[r];
}if(ans!=lst.size())cout<<1/0;
reverse(all(lst));
for(int x:lst){
cout<<x<<' ';
}cout<<endl;
}
int main(){
//srand(time(0));
//freopen("hotel.in","r",stdin);
//freopen("hotel.out","w",stdout);
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
int tt=1,lolol=0;
// cin>>tt;
while(tt--) {
//cout<<"Case "<<++lolol<<": ";
solve();
}
}
컴파일 시 표준 에러 (stderr) 메시지
subsequence.cpp: In function 'void solve()':
subsequence.cpp:58:9: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
58 | }if(ans!=lst.size())cout<<1/0;
| ~~~^~~~~~~~~~~~
subsequence.cpp:58:29: warning: division by zero [-Wdiv-by-zero]
58 | }if(ans!=lst.size())cout<<1/0;
| ~^~
subsequence.cpp: In function 'int main()':
subsequence.cpp:70:11: warning: unused variable 'lolol' [-Wunused-variable]
70 | int tt=1,lolol=0;
| ^~~~~
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