Submission #685360

#	Time	Username	Problem	Language	Result	Execution time	Memory
685360		Nuraly_Serikbay	Bank (IZhO14_bank)	C++14	0 / 100	0 ms	340 KiB

bank

/* Speech to the young */

//#include <bits/stdc++.h>
#include <map>
#include <set>
#include <list>
#include <cmath>
#include <ctime>
#include <deque>
#include <queue>
#include <stack>
#include <string>
#include <bitset>
#include <cstdio>
#include <limits>
#include <vector>
#include <climits>
#include <cstring>
#include <cstdlib>
#include <fstream>
#include <numeric>
#include <sstream>
#include <cassert>
#include <iomanip>
#include <iostream>
#include <algorithm>
#include <stdio.h>
#include <fstream>
#include <unordered_map>
/*
#pragma GCC optimize("inline")
#pragma GCC optimize("-fgcse,-fgcse-lm")
#pragma GCC optimize("-ftree-pre,-ftree-vrp")
#pragma GCC optimize("-ffast-math")
#pragma GCC optimize("-fipa-sra")
#pragma GCC optimize("-fpeephole2")
#pragma GCC optimize("-fsched-spec")
#pragma GCC optimize("Ofast,no-stack-protector")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,tune=native")
#pragma GCC optimize("unroll-loops")
*/
 

using namespace std;

#define mp make_pair
#define pb push_back
#define all(x) x.begin(),x.end()
#define F first
#define S second
#define YOSIK() ios_base::sync_with_stdio(0),cin.tie(0)
#define int long long
#define cube (x) ((x) * (x) * (x))

int gcd (int a, int b) {if (b == 0){return a;}else {return gcd (b, a % b);}}
void pre(int a) { cout<<fixed<<setprecision(a); }
int bitcount (int x) {return __builtin_popcount	(x);}

const int N = 2e5 + 10;
const int INF = 1e18 + 1;
const int MOD = 1e9 + 7;
const int P = 31;
const double eps = 1e-19;
long double pi = 3.1415926535897323;

int n, a[N], m, b[N], dp[30000];

void Solution () {
	cin >> n >> m;
	cin >> a[1];
	dp[0] = 1;
	for (int i = 1; i <= m; ++ i) cin >> b[i];
	for (int i = 1; i <= m; ++ i) {
		for (int j = b[i]; j <= a[1]; ++ j) if (dp[j - b[i]]) dp[j] = 1;
	}
	if (dp[a[1]]) cout << "YES\n";
	else cout << "NO\n";
	return;
}

signed main () {
	YOSIK();
//	precalc();
	int T = 1;
//	cin >> T;
	while (T --) Solution ();
	exit (0);
}

• Subtask 1: 0 / 19
• Subtask 2: 0 / 25
• Subtask 3: 0 / 27
• Subtask 4: 0 / 29