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제출 #685209

#제출 시각아이디문제언어결과실행 시간메모리
685209Farhan_HYGrudanje (COCI19_grudanje)C++14
35 / 70
2090 ms55196 KiB
#include <bits/stdc++.h> #define F first #define S second #define T int t; cin >> t; while(t--) #define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); using namespace std; const int N = 1e5 + 5; const int M = 1e3 + 3; const int inf = 1e18; const int mod = 1e9 + 7; int n, q, a[N]; pair<int, int> p[N], tree[30][4 * N]; string s; pair<int, int> getMax(pair<int, int> p1, pair<int, int> p2) { vector<int> v; v.push_back(p1.F); v.push_back(p1.S); v.push_back(p2.F); v.push_back(p2.S); sort(begin(v), end(v)); return {v[3], v[2]}; } void build(int letter, int node, int tl, int tr) { if (tr == tl) { if (s[tr] == (letter + 'a')) tree[letter][node] = {a[tl], 0}; return; } int mid = (tl + tr) / 2; build(letter, 2 * node, tl, mid); build(letter, 2 * node + 1, mid + 1, tr); tree[letter][node] = getMax(tree[letter][2 * node], tree[letter][2 * node + 1]); } pair<int, int> get(int letter, int node, int tl, int tr, int l, int r) { if (tr < l || tl > r) return {0, 0}; if (l <= tl && tr <= r) return tree[letter][node]; int mid = (tl + tr) / 2; pair<int, int> p1 = get(letter, 2 * node, tl, mid, l, r); pair<int, int> p2 = get(letter, 2 * node + 1, mid + 1, tr, l, r); return getMax(p1, p2); } main() { IOS cin >> s; n = s.size(); s = '.' + s; cin >> q; for(int i = 1; i <= q; i++) cin >> p[i].F >> p[i].S; sort(p, p + q + 1); for(int i = 1; i <= n; i++) { int x; cin >> x; a[x] = i; } int mx = 0; for(int j = 0; j < 26; j++) build(j, 1, 1, n); for(int i = 1; i <= q; i++) { for(int j = 0; j < 26; j++) { int l = p[i].F, r = p[i].S; int need = get(j, 1, 1, n, l, r).S; mx = max(mx, need); } } cout << mx << '\n'; }

컴파일 시 표준 에러 (stderr) 메시지

grudanje.cpp:10:17: warning: overflow in conversion from 'double' to 'int' changes value from '1.0e+18' to '2147483647' [-Woverflow]
   10 | const int inf = 1e18;
      |                 ^~~~
grudanje.cpp:46:1: warning: ISO C++ forbids declaration of 'main' with no type [-Wreturn-type]
   46 | main() {
      | ^~~~
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