이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// Success consists of going from failure to failure without loss of enthusiasm
#include <bits/stdc++.h>
using namespace std;
#define nl '\n'
#define mp make_pair
#define f first
#define s second
using pi = pair<int, int>;
using ll = long long;
using T = array<ll, 3>;
const ll INFL = ll(1e18) + 1008;
int main() {
cin.tie(0)->sync_with_stdio(0);
int N, M; cin >> N >> M;
vector<int> C(M), U(M), V(M); vector<ll> P(M);
vector<vector<vector<pi>>> adj(N);
vector<vector<int>> co(N, {-1});
for(int i = 0; i < M; i++) {
cin >> U[i] >> V[i] >> C[i] >> P[i]; --U[i], --V[i], --C[i];
co[U[i]].push_back(C[i]);
co[V[i]].push_back(C[i]);
}
vector<vector<ll>> dst(N);
vector<vector<bool>> vis(N);
for(int u = 0; u < N; u++) {
sort(begin(co[u]), end(co[u]));
co[u].erase(unique(begin(co[u]), end(co[u])), end(co[u]));
dst[u].assign(size(co[u]) + 1, INFL);
vis[u].assign(size(co[u]) + 1, 0);
adj[u].assign(size(co[u]) + 1, {});
}
auto get = [&](int x, int c) { return lower_bound(begin(co[x]), end(co[x]), c) - begin(co[x]); };
for(int i = 0; i < M; i++) {
adj[U[i]][get(U[i], C[i])].push_back(mp(V[i], i));
adj[V[i]][get(V[i], C[i])].push_back(mp(U[i], i));
}
priority_queue<T, vector<T>, greater<T>> q;
q.push({dst[0][0] = 0, 0, -1});
while(size(q) > 0) {
auto [d, u, c] = q.top(); q.pop();
int CO = (c == -1 ? 0 : get(u, c));
if (vis[u][CO]) continue;
vis[u][CO] = 1;
if (CO == 0) {
for(int x = 1; x < int(size(co[u])); x++) {
ll S = 0;
for(auto e : adj[u][x]) S += P[e.s];
for(auto e : adj[u][x]) {
int v, i; tie(v, i) = e;
int cv = get(v, co[u][x]);
ll w = min(S - P[i], P[i]);
if (dst[v][cv] > dst[u][CO]) q.push({dst[v][cv] = dst[u][CO], v, co[u][x]});
if (dst[v][0] > (dst[u][CO]+w)) q.push({dst[v][0] = (dst[u][CO]+w), v, -1});
}
}
} else {
ll S = 0;
for(auto e : adj[u][CO]) S += P[e.s];
for(auto e : adj[u][CO]) {
int v, i; tie(v, i) = e;
ll w = S - P[i];
if (dst[v][0] > (dst[u][CO]+w)) q.push({dst[v][0] = (dst[u][CO]+w), v, -1});
}
}
}
cout << (dst[N-1][0] == INFL ? -1 : dst[N-1][0]) << nl;
return 0;
}
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