답안 #682913

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
682913	2023-01-17T08:49:57 Z	ghostwriter	Pipes (CEOI15_pipes)	C++17	20 / 100	5000 ms	48892 KB

pipes

// #pragma GCC optimize ("Ofast")
// #pragma GCC target ("avx2")
#include <bits/stdc++.h>
using namespace std;
#ifdef LOCAL
    #include <debug.h>
#else
    #define debug(...)
#endif
#define ft front
#define bk back
#define st first
#define nd second
#define ins insert
#define ers erase
#define pb push_back
#define pf push_front
#define _pb pop_back
#define _pf pop_front
#define lb lower_bound
#define ub upper_bound
#define mtp make_tuple
#define bg begin
#define ed end
#define all(x) (x).bg(), (x).ed()
#define sz(x) (int)(x).size()
// #define int long long
typedef long long ll; typedef unsigned long long ull;
typedef double db; typedef long double ldb;
typedef pair<int, int> pi; typedef pair<ll, ll> pll;
typedef vector<int> vi; typedef vector<ll> vll; typedef vector<pi> vpi; typedef vector<pll> vpll;
typedef string str;
#define FOR(i, l, r) for (int i = (l); i <= (r); ++i)
#define FOS(i, r, l) for (int i = (r); i >= (l); --i)
#define FRN(i, n) for (int i = 0; i < (n); ++i)
#define FSN(i, n) for (int i = (n) - 1; i >= 0; --i)
#define EACH(i, x) for (auto &i : (x))
#define WHILE while
template<typename T> T gcd(T a, T b) { T d2 = (a | b) & -(a | b); a /= d2; b /= d2; WHILE(b) { a = a % b; swap(a, b); } return a * d2; }
template<typename T> T lcm(T a, T b) { return a / gcd(a, b) * b; }
void _assert(bool statement) { if (statement) return; cerr << "\n>> Assertion failed!\n"; exit(0); }
void _assert(bool statement, const str &message) { if (statement) return; cerr << "\n>> Assertion failed: " << message << '\n'; exit(0); }
void _error(const str &message) { cerr << "\n>> Error: " << message << '\n'; exit(0); }
#define file "TEST"
mt19937 rd(chrono::steady_clock::now().time_since_epoch().count());
ll rand(ll l, ll r) { return uniform_int_distribution<ll>(l, r)(rd); }
/*
----------------------------------------------------------------
    END OF TEMPLATE
----------------------------------------------------------------
    Tran The Bao - ghostwriter
    Training for VOI23 gold medal
----------------------------------------------------------------
    GOAT
----------------------------------------------------------------
*/
int n, m;
struct OnlineBridge {
	#define matrix vector<vi>
	int n;
	vi h, s, c1; // heights, size of the component and markup array
	matrix adj, p; // adjacent matrix, sparse table parent
	vpi bridge; // vector that contains all the bridges
	map<pi, bool> c; // markup map to mark all edge that's not bridge
	OnlineBridge(int n) : n(n) { // 1 indexed
		h.resize(n + 1, 0);
		s.resize(n + 1, 0);
		c1.resize(n + 1, 0);
		adj.resize(n + 1);
		p.resize(n + 1);
		FRN(i, n + 1) p[i].resize(17, 0);
		FOR(i, 1, n) s[i] = 1;
	}
	int getp(int u) { // get parent of current components
		FSN(j, 17)
			if (p[u][j])
				u = p[u][j];
		return u;
	}
	void dfs(int u, int pn) { // reorder tree when a new edge is added (update all needed stat)
		FOR(i, 1, 16) p[u][i] = p[p[u][i - 1]][i - 1];
		EACH(v, adj[u]) {
			if (v == pn) continue;
			h[v] = h[u] + 1;
			p[v][0] = u;
			dfs(v, u);
		}
	}
	int lca(int x, int y) { // find lowest common ancestor
		if (h[x] > h[y]) swap(x, y);
		int diff = h[y] - h[x];
		FRN(i, 17)
			if (diff & (1 << i))
				y = p[y][i];
		if (x == y) return x;
		FSN(i, 17)
			if (p[x][i] != p[y][i]) {
				x = p[x][i];
				y = p[y][i];
			}
		return p[x][0];
	}
	bool mark(int x, int y) { // mark edge (x, y), if (x, y) is already marked then return 0 else 1
		if (x > y) swap(x, y);
		if (c.count({x, y})) return 0;
		c[{x, y}] = 1;
		return 1;
	}
	void add(int x, int y) { // process new edge added to graph
		int px = getp(x);
		int py = getp(y);
		if (px == py) {
			int LCA = lca(x, y);
			WHILE(y != LCA) {
				int pn = p[y][0];
				if (!mark(pn, y)) break;
				y = pn;
			}
			WHILE(x != LCA) {
				int pn = p[x][0];
				if (!mark(pn, x)) break;
				x = pn;
			}
		}
		else {
			if (s[px] < s[py]) {
				swap(x, y);
				swap(px, py);
			}
			adj[x].pb(y);
			adj[y].pb(x);
			h[y] = h[x] + 1;
			p[y][0] = x;
			dfs(y, x);
			s[px] += s[py];
		}
	}
	void dfs1(int u, int pn) {
		c1[u] = 1;
		EACH(v, adj[u]) {
			if (v == pn) continue;
			int un = u, vn = v;
			if (un > vn) swap(un, vn);
			if (!c.count({un, vn})) bridge.pb({un, vn});
			dfs1(v, u);
		}
	}
	vpi getBridge() {
		FOR(i, 1, n) c1[i] = 0;
		bridge.clear();
		FOR(i, 1, n)
			if (!c1[i])
				dfs1(i, 0);
		return bridge;
	}
};
void reinit(int test_id) {

}
void input(int test_id) {
	cin >> n >> m;
}
void solve(int test_id) {
	OnlineBridge ob(n);
	WHILE(m--) {
		int u, v;
		cin >> u >> v;
		ob.add(u, v);
	}
	vpi ans = ob.getBridge();
	EACH(i, ans) cout << i.st << ' ' << i.nd << '\n';
}
signed main() {
    ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
    // freopen(file".inp", "r", stdin);
    // freopen(file".out", "w", stdout);
    int test_num = 1;
    // cin >> test_num; // comment if the problem does not requires multitest
    FOR(i, 1, test_num) {
        input(i); // input in noninteractive sections for case #i
        solve(i); // main function to solve case #i
        reinit(i); // reinit global data to default used in case #i
    }
    #ifdef LOCAL
        cerr << "\nTime: " << setprecision(5) << fixed << (ldb)clock() / CLOCKS_PER_SEC << "ms.\n";
    #endif
    return 0;
}
/*
----------------------------------------------------------------
From Benq:
    stuff you should look for
        * int overflow, array bounds
        * special cases (n=1?)
        * do smth instead of nothing and stay organized
        * WRITE STUFF DOWN
        * DON'T GET STUCK ON ONE APPROACH
----------------------------------------------------------------
*/

Subtask #1
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Correct	1 ms	328 KB	Output is correct
2	Incorrect	1 ms	340 KB	Wrong number of edges
3	Halted	0 ms	0 KB	-

Subtask #2
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Incorrect	10 ms	1408 KB	Wrong number of edges
2	Halted	0 ms	0 KB	-

Subtask #3
10.0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Correct	427 ms	6608 KB	Output is correct
2	Correct	350 ms	6316 KB	Output is correct

Subtask #4
10.0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Correct	785 ms	12108 KB	Output is correct
2	Correct	894 ms	13732 KB	Output is correct

Subtask #5
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Runtime error	1352 ms	21868 KB	Memory limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #6
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Runtime error	3201 ms	37004 KB	Memory limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #7
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	5067 ms	48892 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #8
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	5005 ms	42104 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #9
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	5082 ms	46080 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #10
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	5018 ms	46692 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

답안 #682913

Compilation message