제출 #682225

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
682225		vjudge1	Road Construction (JOI21_road_construction)	C++17	32 / 100	4952 ms	2097152 KiB

road_construction

#include "bits/stdc++.h"
using namespace std;

// #define ORD_SET
// #define ROPE
#ifdef ORD_SET
    #include <ext/pb_ds/assoc_container.hpp>
    #include <ext/pb_ds/tree_policy.hpp>
    using namespace __gnu_pbds;
    template<typename T>
    using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#endif
#ifdef ROPE
    #include <ext/rope>
    using namespace __gnu_cxx;
#endif        

// #pragma comment(linker, "/stack:200000000")
// #pragma GCC optimize("Ofast")
// #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,avx2,tune=native")

using ll = long long;
using ld = long double;
#define pb push_back
#define ff first
#define ss second
#define sz(x) (ll)(x).size()
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
// #define ll int
void freopen(string s) { freopen((s + ".in").c_str(), "r", stdin); freopen((s + ".out").c_str(), "w", stdout); }
void NotInteractive() { ios_base::sync_with_stdio(false); cin.tie(NULL); }
void pre(ll a) { cout<<fixed<<setprecision(a); }
ll bit(ll x) { return __builtin_popcountll(x); }
ll binpow(ll x, ll y, ll z) { ll pow = 1; while(y) { if(y&1) pow *= x, pow %= z; x *= x, x %= z; y >>= 1; } return pow; }
template<typename T> T gcd(T a, T b) { if(b==0) return a; return gcd(b, a%b); }
template<typename T> T lcm(T a, T b) { return a/gcd(a, b)*b; }
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

struct sn { ll l, r, x; }; // a.swap(b)
ll B = 316;
const ll mod = (ll)1e9+7;
const ll inf = (ll)1e18+7;
const ll MX = LLONG_MAX;
const ll MN = LLONG_MIN;
const ld P = acos(-1.0);
const ll N = (ll)3e5+5;
ll x[N], y[N];

void kigash() {
    ll n, k;
    cin>>n>>k;
    for(ll i=1; i<=n; i++) cin>>x[i]>>y[i];
    if(k<=10 && n>1000) {
        vector<pair<pair<ll, ll>, ll>> v;
        for(ll i=1; i<=n; i++) v.pb({{x[i], y[i]}, i});
        sort(all(v));
        vector<ll> ans;
        ll mn = MX;
        map<pair<ll, ll>, ll> used;
        for(ll i=0; i<n; i++) {
            for(ll j=i+1; j<min(i+11, n); j++) {
                ll d = abs(v[i].ff.ff-v[j].ff.ff)+abs(v[i].ff.ss-v[j].ff.ss);
                ans.pb(d);
                used[{v[j].ss, v[i].ss}] = used[{v[i].ss, v[j].ss}] = 1;
            }
        }
        v.clear();
        for(ll i=1; i<=n; i++) v.pb({{y[i], x[i]}, i});
        sort(all(v));
        for(ll i=0; i<n; i++) {
            for(ll j=i+1; j<min(i+11, n); j++) {
                if(used[{v[j].ss, v[i].ss}]) continue;
                ll d = abs(v[i].ff.ff-v[j].ff.ff)+abs(v[i].ff.ss-v[j].ff.ss);
                ans.pb(d);
            }
        }
        sort(all(ans));
        for(ll i=0; i<k; i++) cout<<ans[i]<<"\n";
        return;
    }
    vector<ll> ans;
    for(ll i=1; i<=n; i++) {
        for(ll j=i+1; j<=n; j++) ans.pb(abs(x[i]-x[j])+abs(y[i]-y[j]));
    }
    sort(all(ans));
    for(ll i=0; i<k; i++) cout<<ans[i]<<"\n";
    return;
}

signed main(/**/) {
    // freopen("");
    NotInteractive();
    // precalc();
    
    ll tt = 1;
    // cin>>tt;
    for(ll i=1; i<=tt; i++) kigash();
    
    exit(0);
}

컴파일 시 표준 에러 (stderr) 메시지

road_construction.cpp: In function 'void kigash()':
road_construction.cpp:59:12: warning: unused variable 'mn' [-Wunused-variable]
   59 |         ll mn = MX;
      |            ^~
road_construction.cpp: In function 'void freopen(std::string)':
road_construction.cpp:31:33: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   31 | void freopen(string s) { freopen((s + ".in").c_str(), "r", stdin); freopen((s + ".out").c_str(), "w", stdout); }
      |                          ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
road_construction.cpp:31:75: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   31 | void freopen(string s) { freopen((s + ".in").c_str(), "r", stdin); freopen((s + ".out").c_str(), "w", stdout); }
      |                                                                    ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 5 / 5
• Subtask 2: 0 / 6
• Subtask 3: 7 / 7
• Subtask 4: 20 / 20
• Subtask 5: 0 / 27
• Subtask 6: 0 / 35