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답안 #681293

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
681293 2023-01-12T16:59:16 Z vjudge1 Skyscraper (JOI16_skyscraper) C++17
100 / 100
 61 ms 23924 KB 
#include <bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef pair<int,int> ii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef long double ld;

#define fi first
#define se second
#define pb push_back
#define mp make_pair

ll dp[101][101][1001][3]; 
/*
dp[i][j][k][l] : 
i - number of numbers placed
j - number of connected components
k - total sum currently (filling empty spaces with a_{i} (0-indexed)
l - number of endpoints that are filled
*/
ll a[101];
const ll MOD = 1e9 + 7;

int main()
{
	ios_base::sync_with_stdio(0); cin.tie(0);
	int n, l;
	cin>>n>>l;
	for(int i = 0; i < n; i++)
	{
		cin>>a[i];
	}
	sort(a, a + n);
	if(n == 1) //special case
	{
		cout << 1;
		return 0;
	}
	a[n] = 10000; //inf for simplicity
	if(a[1] - a[0] <= l) dp[1][1][a[1] - a[0]][1] = 2; //fill a[0] at one of the endpoints, there are 2 endpoints to fill.
	if(2*(a[1] - a[0]) <= l) dp[1][1][2*(a[1] - a[0])][0] = 1; //fill a[0] in the middle, positions doesn't matter.
	
	for(int i = 1; i < n; i++)
	{
		int diff = a[i + 1] - a[i]; //this thing is "INF" if i = n - 1.
		for(int j = 1; j <= i; j++)
		{
			for(int k = 0; k <= l; k++)
			{
				for(int z = 0; z < 3; z++)
				{
					if(!dp[i][j][k][z]) continue; //this value does not exist
					//First, we try to fill one of the ends
					if(z < 2 && k + diff*(2*j - z - 1) <= l) //there are 2*j - z - 1 positions that we're supposed to "upgrade" (-1 because one of the positions is merged with the endpoints after this move)
					{
						if(i == n - 1)
						{
							dp[i + 1][j][k + diff*(2*j - z - 1)][z + 1] = (dp[i + 1][j][k + diff*(2*j - z - 1)][z + 1] + dp[i][j][k][z]*(2-z)*j)%MOD; //we have j con. comp. to choose to merge with
						}
						else if(z == 0 || j > 1) //otherwise this coincides with i == n - 1
						{
							dp[i + 1][j][k + diff*(2*j - z - 1)][z + 1] = (dp[i + 1][j][k + diff*(2*j - z - 1)][z + 1] + dp[i][j][k][z]*(2-z)*(j-z))%MOD; //can only merge with the con comp. that are not connected to ends.
						}
						if(k + diff*(2*j - z + 1) <= l) //now we create a new cc.
						{
							dp[i + 1][j + 1][k + diff*(2*j - z + 1)][z + 1] = (dp[i + 1][j + 1][k + diff*(2*j - z + 1)][z + 1] + dp[i][j][k][z]*(2-z))%MOD; //we can choose one of the ends to create
						}
					}
					//Next, we dont fill the ends. 
					//Part 1 : Create new cc
					if(k + diff*(2*j - z + 2) <= l) //2 new positions to "upgrade"
					{
						dp[i + 1][j + 1][k + diff*(2*j - z + 2)][z] = (dp[i + 1][j + 1][k + diff*(2*j - z + 2)][z] + dp[i][j][k][z])%MOD; //nothing new happens
					}
					//Part 2 : Stick to one cc
					if(k + diff*(2*j - z) <= l) //no new positions to "upgrade"
					{
						dp[i + 1][j][k + diff*(2*j - z)][z] = (dp[i + 1][j][k + diff*(2*j - z)][z] + dp[i][j][k][z]*(2*j - z))%MOD; //we can merge in 2*j - z possible positions
					}
					//Part 3 : Merge two ccs together
					if((k + diff*(2*j - z - 2) <= l) && (j >= 2) && (i == n - 1 || j > 2 || z < 2))
					{
						if(z == 0)
						{
							dp[i + 1][j - 1][k + diff*(2*j - z - 2)][z] = (dp[i + 1][j - 1][k + diff*(2*j - z - 2)][z] + dp[i][j][k][z]*j*(j-1))%MOD; //there are jP2 possible merges
						}
						if(z == 1)
						{
							dp[i + 1][j - 1][k + diff*(2*j - z - 2)][z] = (dp[i + 1][j - 1][k + diff*(2*j - z - 2)][z] + dp[i][j][k][z]*(j-1)*(j-1))%MOD; //there are (j-1)P2+(j-1) merges
						}
						if(z == 2)
						{
							if(i == n - 1)
							{
								dp[i + 1][j - 1][k + diff*(2*j - z - 2)][z] = (dp[i + 1][j - 1][k + diff*(2*j - z - 2)][z] + dp[i][j][k][z])%MOD; //there's only 1 place it can go.
							}
							else
							{
								dp[i + 1][j - 1][k + diff*(2*j - z - 2)][z] = (dp[i + 1][j - 1][k + diff*(2*j - z - 2)][z] + dp[i][j][k][z]*(j-2)*(j-1))%MOD; //there're (j-2)P2 + 2(j-2) possiblilities
							}
						}
					}
				}
			}
		}
	}
	
	ll answer = 0;
	for(int i = 0; i <= l; i++)
	{
		answer = (answer + dp[n][1][i][2])%MOD; //sum the dp values for all possible sums
	}
	cout << answer << '\n';
	return 0;
}

Subtask #1
5.0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Correct 0 ms 344 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 1 ms 468 KB Output is correct
6 Correct 1 ms 468 KB Output is correct
7 Correct 0 ms 340 KB Output is correct
8 Correct 1 ms 460 KB Output is correct
9 Correct 1 ms 468 KB Output is correct
10 Correct 0 ms 468 KB Output is correct

Subtask #2
15.0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 596 KB Output is correct
2 Correct 1 ms 468 KB Output is correct
3 Correct 1 ms 596 KB Output is correct
4 Correct 1 ms 468 KB Output is correct
5 Correct 1 ms 468 KB Output is correct
6 Correct 1 ms 596 KB Output is correct
7 Correct 1 ms 468 KB Output is correct
8 Correct 1 ms 596 KB Output is correct
9 Correct 1 ms 596 KB Output is correct
10 Correct 1 ms 464 KB Output is correct

Subtask #3
80.0 / 80.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 212 KB Output is correct
2 Correct 0 ms 344 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 1 ms 340 KB Output is correct
5 Correct 1 ms 468 KB Output is correct
6 Correct 1 ms 468 KB Output is correct
7 Correct 0 ms 340 KB Output is correct
8 Correct 1 ms 460 KB Output is correct
9 Correct 1 ms 468 KB Output is correct
10 Correct 0 ms 468 KB Output is correct
11 Correct 1 ms 596 KB Output is correct
12 Correct 1 ms 468 KB Output is correct
13 Correct 1 ms 596 KB Output is correct
14 Correct 1 ms 468 KB Output is correct
15 Correct 1 ms 468 KB Output is correct
16 Correct 1 ms 596 KB Output is correct
17 Correct 1 ms 468 KB Output is correct
18 Correct 1 ms 596 KB Output is correct
19 Correct 1 ms 596 KB Output is correct
20 Correct 1 ms 464 KB Output is correct
21 Correct 1 ms 1108 KB Output is correct
22 Correct 61 ms 23924 KB Output is correct
23 Correct 44 ms 7992 KB Output is correct
24 Correct 42 ms 11980 KB Output is correct
25 Correct 54 ms 9220 KB Output is correct
26 Correct 42 ms 8488 KB Output is correct
27 Correct 21 ms 9708 KB Output is correct
28 Correct 26 ms 11908 KB Output is correct
29 Correct 44 ms 16340 KB Output is correct
30 Correct 51 ms 9452 KB Output is correct