제출 #680995

#제출 시각아이디문제언어결과실행 시간메모리
680995jhwest2Financial Report (JOI21_financial)C++17
100 / 100
362 ms15324 KiB
#include <bits/stdc++.h> using namespace std; const int N = 303030; int n, d, a[N], p[N], rr[N]; struct seg { int tree[N * 4]; void update(int a, int v, int l, int r, int x) { if (l == r) { tree[x] = v; return; } int m = (l + r) / 2; if (a <= m) update(a, v, l, m, 2 * x); else update(a, v, m + 1, r, 2 * x + 1); tree[x] = max(tree[2 * x], tree[2 * x + 1]); } int query(int a, int b, int l, int r, int x) { if (b < l || a > r) return 0; if (a <= l && r <= b) return tree[x]; int m = (l + r) / 2; return max(query(a, b, l, m, 2 * x), query(a, b, m + 1, r, 2 * x + 1)); } } t1; int par[N], sz[N], dp[N]; bool chk[N]; void init() { iota(par, par + N, 0); } int Find(int a) { return par[a] = ((par[a] == a) ? a : Find(par[a])); } void Union(int a, int b) { a = Find(a); b = Find(b); if (a != b) { par[b] = a; sz[a] += sz[b]; } } int main() { cin.tie(0); ios_base::sync_with_stdio(0); cin >> n >> d; vector<int> v; for (int i = 1; i <= n; i++) cin >> a[i]; for (int i = 1; i <= n; i++) p[i] = i; sort(p + 1, p + 1 + n, [&](auto i, auto j) { return a[i] > a[j]; }); init(); set<int> st; // stores first positions for length >= d segments for (int i = 1, j = 1; i <= n; i = j) { while (j <= n && a[p[i]] == a[p[j]]) ++j; // cout << i << ' ' << j << '\n'; // for (int x : st) // cout << x << ' '; // cout << "!\n"; for (int k = i; k < j; k++) { auto it = st.lower_bound(p[k]); if (it == st.end()) rr[p[k]] = n; else rr[p[k]] = min(n, *it + d - 1); } for (int k = i; k < j; k++) { int x = p[k]; chk[x] = 1; sz[x] = 1; if (d == 1) st.insert(x); if (x > 1 && chk[x - 1]) { int a = Find(x - 1); int b = Find(x); if (a != b) { if (sz[b] >= d) st.erase(b); bool f = false; if (sz[a] < d) f = true; Union(a, b); if (f && sz[a] >= d) st.insert(a); } } if (x < n && chk[x + 1]) { int a = Find(x); int b = Find(x + 1); if (a != b) { if (sz[b] >= d) st.erase(b); bool f = false; if (sz[a] < d) f = true; Union(a, b); if (f && sz[a] >= d) st.insert(a); } } } } for (int i = 1, j = 1; i <= n; i = j) { while (j <= n && a[p[i]] == a[p[j]]) ++j; for (int k = i; k < j; k++) dp[p[k]] = t1.query(p[k] + 1, rr[p[k]], 1, n, 1) + 1; for (int k = i; k < j; k++) t1.update(p[k], dp[p[k]], 1, n, 1); } cout << *max_element(dp + 1, dp + 1 + n); }
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