제출 #679172

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
679172		speedyArda	Art Exhibition (JOI18_art)	C++14	100 / 100	529 ms	19916 KiB

art

#pragma GCC optimize ("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization ("unroll-loops")
#include "bits/stdc++.h"
#define pb push_back
#define vll vector<long long>
#define vb vector<bool>
#define vi vector<int>
#define vs vector<string>
#define vpii vector< pair<int, int> >
#define pii pair<int, int>
#define pbb pair<bool, bool>
#define pll pair<long long, long long>
#define vvi vector< vector<int> > 
#define ld long double
#define mp make_pair
#define FASTIO ios_base::sync_with_stdio(false); cin.tie(NULL);
#define all(x) (x).begin(),(x).end()
#define rall(x) (x).rbegin(),(x).rend()
using namespace std;
using ll = long long;
const int MAXN = 5e5+5;
pair<ll, ll> in[MAXN];
// Solution O(n). Add the differences between sizes as negatives in the array. The rest is Kadane Algorithm. (Maximum contiguous sum)
int main() 
{
    int n;
    cin >> n;
    for(int i = 0; i < n; i++)  
        cin >> in[i].first >> in[i].second;
    sort(in, in + n);
    reverse(in, in + n);
    vector< ll > elems;
    elems.pb(in[0].second);
    for(int i = 1; i < n; i++)
    {
        if(in[i].first != in[i - 1].first)
            elems.pb(in[i].first - in[i - 1].first);
        elems.pb(in[i].second);
    } 
    ll ans = 0, temp = 0;
    for(int i = 0; i < elems.size(); i++)
    {
        temp += elems[i];
        ans = max(ans, temp);
        if(temp < 0)
            temp = 0;
    }

    cout << ans << "\n";
}

컴파일 시 표준 에러 (stderr) 메시지

art.cpp:3: warning: ignoring '#pragma GCC optimization' [-Wunknown-pragmas]
    3 | #pragma GCC optimization ("unroll-loops")
      | 
art.cpp: In function 'int main()':
art.cpp:42:22: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   42 |     for(int i = 0; i < elems.size(); i++)
      |                    ~~^~~~~~~~~~~~~~

• Subtask 1: 10 / 10
• Subtask 2: 20 / 20
• Subtask 3: 20 / 20
• Subtask 4: 50 / 50