제출 #67908

#제출 시각아이디문제언어결과실행 시간메모리
67908aquablitz11전선 연결 (IOI17_wiring)C++14
100 / 100
136 ms18084 KiB
#include <bits/stdc++.h> #include "wiring.h" using namespace std; using pii = pair<int, int>; using ll = long long; const int N = 200010; const int INF = 2e9+2; int sz[N]; ll dp[N], qsl[N], qsr[N]; ll min_total_length(vector<int> R, vector<int> B) { vector<pii> all; for (auto x : R) all.emplace_back(x, 0); for (auto x : B) all.emplace_back(x, 1); int n = all.size(); all.emplace_back(-1, -1); sort(all.begin(), all.end()); R.insert(R.begin(), -INF); R.insert(R.end(), INF); B.insert(B.begin(), -INF); B.insert(B.end(), INF); int z = 0; for (int i = 1; i <= n; ++i) { if (all[i].second != all[i-1].second) z = 0; sz[i] = ++z; } for (int i = 1; i <= n; ++i) qsl[i] = qsl[i-1] + all[i].first; for (int i = n; i >= 1; --i) qsr[i] = qsr[i+1] + (INF-all[i].first); for (int i = 1; i <= n; ++i) { ll nl, nr; // nearest opposite color of all[i].second to the left and to the right if (all[i].second == 0) { nl = *(lower_bound(B.begin(), B.end(), all[i].first)-1); nr = *lower_bound(B.begin(), B.end(), all[i].first); } else { nl = *(lower_bound(R.begin(), R.end(), all[i].first)-1); nr = *lower_bound(R.begin(), R.end(), all[i].first); } dp[i] = dp[i-1]+min(all[i].first-nl, nr-all[i].first); ll j = -1; // from j to i there will be one color followed by another color with equal amount if (sz[i-sz[i]] >= sz[i]) j = i-sz[i]-sz[i]+1; if (j != -1) { ll ml = (i+j)/2; ll mr = (i+j+1)/2; ll c = i-ml; ll cl = (all[ml].first*1ll*c) - (qsl[ml]-qsl[j-1]); ll cr = (INF-all[mr].first)*1ll*c - (qsr[mr]-qsr[i+1]); ll cm = (all[mr].first-all[ml].first)*c; dp[i] = min(dp[i], cl+cr+cm+dp[j-1]); } } return dp[n]; }
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