Submission #678299

#	Time	Username	Problem	Language	Result	Execution time	Memory
678299		stanislavpolyn	Newspapers (CEOI21_newspapers)	C++17	4 / 100	1 ms	340 KiB

newspapers

#include <bits/stdc++.h>

//#pragma GCC optimize("O3")

#define fr(i, a, b) for (int i = (a); i <= (b); ++i)
#define rf(i, a, b) for (int i = (a); i >= (b); --i)
#define fe(x, y) for (auto& x : y)

#define fi first
#define se second
#define pb push_back
#define mp make_pair
#define mt make_tuple

#define all(x) (x).begin(), (x).end()
#define pw(x) (1LL << (x))
#define sz(x) (int)(x).size()

using namespace std;

//mt19937_64 rng(chrono::system_clock::now().time_since_epoch().count());

mt19937_64 rng(228);

#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template <typename T>
using oset = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define fbo find_by_order
#define ook order_of_key

template <typename T>
bool umn(T& a, T b) {
    return a > b ? a = b, 1 : 0;
}
template <typename T>
bool umx(T& a, T b) {
    return a < b ? a = b, 1 : 0;
}

using ll = long long;
using ld = long double;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
template <typename T>
using ve = vector<T>;

const int N = 1005;

int n, m;
ve<int> g[N];
int vis[N];

void dfs(int v) {
    vis[v] = 1;
    fe (to, g[v]) {
        if (!vis[to]) {
            dfs(to);
        } else {
            if (vis[to] == 1) {
                cout << "NO\n";
                exit(0);
            }
        }
    }
    vis[v] = 2;
}

int main() {
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#else
    ios::sync_with_stdio(0);
    cin.tie(0);
#endif
//    cout << "YES\n";
//    return 0;

    cin >> n >> m;
    fr (i, 1, m) {
        int a, b;
        cin >> a >> b;

        g[a].pb(b);
        g[b].pb(a);
    }
//
//    fr (i, 1, n) {
//        if (!vis[i]) {
//            dfs(i);
//        }
//    }

    cout << "YES\n";
    ve<int> ans;

    fr (i, 1, n) ans.pb(i);

    cout << sz(ans) << "\n";
    fe (x, ans) {
        cout << x << " ";
    }
    cout << "\n";


    return 0;
}

• Subtask 1: 0 / 12
• Subtask 2: 4 / 8
• Subtask 3: 0 / 80