이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <vector>
#include <set>
#include <queue>
#include <deque>
#include <map>
#include <stack>
#include <algorithm>
#include <cmath>
#include <iomanip>
#include <climits>
using namespace std;
using ll = long long;
int n;
vector<int> clr;
vector<vector<int>> gp;
vector<vector<vector<int>>> dp;
void DPcreator(int u, int p, int nerk)
{
multiset<pair<int, int>> st;
bool impossible = 0;
for (int& v : gp[u])
{
if (v == p) continue;
if (dp[v][0][nerk] < 2e9) st.insert({ dp[v][0][nerk], 0 });
if (dp[v][1][nerk] < 2e9) st.insert({ dp[v][1][nerk], 1 });
if (dp[v][0][nerk] >= 2e9 && dp[v][1][nerk] >= 2e9) impossible = 1;
}
int sum = 0, cnt = clr[u] + nerk, q = gp[u].size() - (p != -1);
int f0 = -1, f1 = -1, s0 = -1, s1 = -1;
for (pair<int, int> i : st)
{
if (q)
{
q--;
cnt += i.second;
sum += i.first;
i.second ? (f1 = i.first) : (f0 = i.first);
}
else
{
if (i.second && s1 == -1) s1 = i.first;
if (!i.second && s0 == -1) s0 = i.first;
}
}
int NotChanged = sum + nerk;
// Changing...
if ((f0 == -1 || s1 == -1) && (f1 == -1 || s0 == -1)) sum = 2e9;
else if (f0 != -1 && s1 != -1 && f1 != -1 && s0 != -1) sum += min(s1 - f0, s0 - f1);
else if (f0 == -1 || s1 == -1) sum += s0 - f1;
else sum += s1 - f0;
int Changed = sum + nerk;
//
if (impossible) NotChanged = Changed = 2e9;
//
if (cnt & 1) dp[u][nerk][0] = Changed, dp[u][nerk][1] = NotChanged;
else dp[u][nerk][0] = NotChanged, dp[u][nerk][1] = Changed;
}
void dfs(int u, int p)
{
if (gp[u].size() == 1 && u != 0)
{
if (clr[u])
{
dp[u][0][0] = 2e9;
dp[u][0][1] = 0;
dp[u][1][0] = 1;
dp[u][1][1] = 2e9;
}
else
{
dp[u][0][0] = 0;
dp[u][0][1] = 2e9;
dp[u][1][0] = 2e9;
dp[u][1][1] = 1;
}
return;
}
for (int& v : gp[u])
{
if (v == p) continue;
if (dp[v][0][0] == -1) dfs(v, u);
}
DPcreator(u, p, 0);
DPcreator(u, p, 1);
}
int main() {
int n; cin >> n;
gp = vector<vector<int>>(n);
dp = vector<vector<vector<int>>>(n, { {-1, -1}, {-1, -1} });
for (int i = 1; i < n; i++)
{
int u, v; cin >> u >> v;
gp[--u].push_back(--v);
gp[v].push_back(u);
}
clr = vector<int>(n);
for (int& i : clr) cin >> i;
dfs(0, -1);
int ans = min(dp[0][0][0], dp[0][1][0]);
if (ans >= 2e9) cout << "impossible\n";
else cout << ans << endl;
return 0;
}
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