이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
void build(vector<int>& a, vector<int>& segtree, int x, int l, int r){
if (l == r){
segtree[x] = a[l];
return;
}
int m = (l+r)/2;
build(a, segtree, 2*x, l, m);
build(a, segtree, 2*x+1, m+1, r);
segtree[x] = segtree[2*x]^segtree[2*x+1];
}
void update(vector<int>&a, vector<int>& segtree, int x, int l, int r, int i, int v){
if (i < l or i > r) return;
else if (l == r){
segtree[x] = v;
a[l] = v;
}
else{
int m = (l+r)/2;
if (i <= m) update(a, segtree, 2*x, l, m, i, v);
else update(a, segtree, 2*x+1, m+1, r, i, v);
segtree[x] = segtree[2*x]^segtree[2*x+1];
}
}
int range(vector<int>& segtree, int x, int l, int r, int lx, int rx){
if (l >= lx && r <= rx) return segtree[x];
else if (l > rx or r < lx) return 0;
else{
int m = (l+r)/2;
int xor1 = range(segtree, 2*x, l, m, lx, rx);
int xor2 = range(segtree, 2*x+1, m+1, r, lx, rx);
return xor1^xor2;
}
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int n, q;
cin >> n >> q;
int n1, n2;
if (n%2 == 0){
n1 = n/2;
n2 = n1;
}
else{
n1 = n/2 + 1;
n2 = n/2;
}
vector<int> aEven(n1);
vector<int> aOdd(n2);
vector<int> SegtreeEven(4*n1, 0);
vector<int> SegtreeOdd(4*n2, 0);
for (int i = 0; i < n; i++){
if (i%2 == 0) cin >> aEven[i/2];
else cin >> aOdd[i/2];
}
build(aEven, SegtreeEven, 1, 0, n1-1);
if (n2 >= 1){
build(aOdd, SegtreeOdd, 1, 0, n2-1);
}
int op, i, v;
while (q--){
cin >> op >> i >> v;
if (op == 1){
if ((i-1)%2 == 0) update(aEven, SegtreeEven, 1, 0, n1-1, (i-1)/2, v);
else update(aOdd, SegtreeOdd, 1, 0, n2-1, (i-1)/2, v);
}
else{
int Range = v-i+1;
if (Range%2 == 0) cout << 0 << "\n";
else if ((i-1)%2 == 0) cout << range(SegtreeEven, 1, 0, n1-1, (i-1)/2, (v-1)/2) << "\n";
else cout << range(SegtreeOdd, 1, 0, n2-1, (i-1)/2, (v-1)/2) << "\n";
}
}
return 0;
}
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