이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <cstdio>
#pragma GCC optimize("O3")
#define endl '\n'
using namespace std;
void allocate_tickets(vector <vector <int> > r);
long long find_maximum(int k, vector <vector <int> > x) {
int n = (int)x.size(), m = (int)x[0].size();
vector <int> taken(n, k);
int balance = 0;
priority_queue <pair <int, int> > pq;
for (int i = 0; i < n; i++) {
taken[i] = k;
balance += k;
pq.push({-x[i][m-k]-x[i][0], i});
}
while (balance > 0) {
pair <int, int> curr = pq.top();
pq.pop();
balance -= 2;
taken[curr.second]--;
if (taken[curr.second] != 0)
pq.push({-x[curr.second][m-taken[curr.second]]-x[curr.second][k-taken[curr.second]], curr.second});
}
long long ans = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j < k-taken[i]; j++)
ans -= x[i][j];
for (int j = m-taken[i]; j < m; j++)
ans += x[i][j];
}
vector <pair <int, pair <int, int> > > vec;
for (int i = 0; i < n; i++) {
for (int j = 0; j < k - taken[i]; j++)
vec.push_back({x[i][j], {-i-1, j}});
for (int j = m - taken[i]; j < m; j++)
vec.push_back({x[i][j], {i, j}});
}
sort (vec.begin(), vec.end());
set <pair <int, int> > s;
vector <vector <int> > r(n, vector <int> (m, -1));
vector <vector <bool> > used(k, vector <bool> (n, false));
for (int i = 0; i < k; i++)
s.insert({0, i});
for (auto i: vec)
if (i.second.first < 0) {
for (auto it = prev(s.end()); ; it--) {
if (!used[it->second][-i.second.first-1]) {
used[it->second][-i.second.first-1] = true;
r[-i.second.first-1][i.second.second] = it->second;
auto to_insert = *it;
to_insert.first--;
s.erase(it);
s.insert(to_insert);
break;
}
}
}
for (auto i: vec)
if (i.second.first >= 0) {
for (auto it = s.begin(); ; it++) {
if (!used[it->second][i.second.first]) {
used[it->second][i.second.first] = true;
r[i.second.first][i.second.second] = it->second;
auto to_insert = *it;
to_insert.first++;
s.erase(it);
s.insert(to_insert);
break;
}
}
}
allocate_tickets(r);
/*
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++)
cout << r[i][j] << " ";
cout << endl;
}
*/
return ans;
}
/*
int n, m, k;
int main() {
cin >> n >> m >> k;
vector <vector <int> > x(n, vector <int> (m));
for (int i = 0; i < n; i++)
for (int j = 0; j < m; j++)
cin >> x[i][j];
cout << find_maximum(k, x) << endl;
}
*/
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