제출 #672566

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
672566		tbzard	슈퍼트리 잇기 (IOI20_supertrees)	C++14	11 / 100	179 ms	22144 KiB

supertrees

#include <bits/stdc++.h>
using namespace std;

void build(vector<vector<int> > b);

bool vis[1002];
int construct(vector<vector<int> > p) {
    int n = (int)p.size();
    vector<vector<int> > ans(n);
    for(int i=0;i<n;i++) ans[i].resize(n);
    for(int i=0;i<n;i++){
        if(vis[i]) continue;
        vis[i] = 1;
        vector<int> c1, c2;
        for(int j=i+1;j<n;j++){
            if(p[i][j] == 1){
                c1.push_back(j);
                vis[j] = 1;
            }
        }
        for(int j=i+1;j<n;j++){
            if(p[i][j] == 2){
                c2.push_back(j);
                vis[j] = 1;
            }
        }

        for(int j=i+1;j<n;j++){
            if(vis[j]) continue;
            for(int k=0;k<(int)c1.size();k++){
                if(p[j][c1[k]] != 0) return 2;
            }
            for(int k=0;k<(int)c2.size();k++){
                if(p[j][c2[k]] != 0) return 3;
            }
        }

        for(int j=0;j<(int)c1.size();j++){
            for(int k=0;k<(int)c1.size();k++){
                if(j == k) continue;
                if(p[c1[j]][c1[k]] != 1) return 4;
            }
        }
        for(int j=0;j<(int)c1.size();j++){
            for(int k=0;k<(int)c2.size();k++){
                if(p[c1[j]][c2[k]] != 2) return 5;
            }
        }

        for(int j=0;j<(int)c2.size();j++){
            for(int k=0;k<(int)c2.size();k++){
                if(j == k) continue;
                if(p[c2[j]][c2[k]] != 2) return 6;
            }
        }

        for(int j=0;j<(int)c1.size();j++){
            ans[i][c1[j]] = 1;
            ans[c1[j]][i] = 1;
        }

        if((int)c2.size() == 1) return 0;
        else if((int)c2.size() > 1){
            ans[i][c2[0]] = 1;
            ans[c2[0]][i] = 1;

            ans[i][c2[c2.size()-1]] = 1;
            ans[c2[c2.size()-1]][i] = 1;
            for(int j=0;j<(int)c2.size()-1;j++){
                ans[c2[j]][c2[j+1]] = 1;
                ans[c2[j+1]][c2[j]] = 1;
            }
        }
    }

    build(ans);
    return 1;
}

• Subtask 1: 11 / 11
• Subtask 2: 0 / 10
• Subtask 3: 0 / 19
• Subtask 4: 0 / 35
• Subtask 5: 0 / 21
• Subtask 6: 0 / 4