제출 #671887

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
671887		viwlesxq	K개의 묶음 (IZhO14_blocks)	C++17	0 / 100	63 ms	82500 KiB

blocks

#include "bits/stdc++.h"
#include "ext/pb_ds/assoc_container.hpp"
#include "ext/pb_ds/tree_policy.hpp"

using namespace std;
using namespace __gnu_pbds;

typedef long long ll;
typedef string str;

#define int long long
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ppf pop_front
#define F first
#define S second
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define sz(x) (int)x.size()
#define ordered_set tree<ll, null_type,less<ll>, rb_tree_tag,tree_order_statistics_node_update>
void freo(str x) {freopen((x + ".in").c_str(), "r", stdin);freopen((x + ".out").c_str(), "w", stdout);}

const int MAXN = 1e5 + 1, MAXK = 1e2;
const ll inf = 1e18 + 7;
vector <vector <ll>> dp(MAXN, vector <ll> (MAXK, inf));
 
signed main() {
	ios::sync_with_stdio(0);
	cin.tie(0);
	cout.tie(0);
	int N, K;
	cin >> N >> K;
	int a[N + 1];
	for (int i = 1; i <= N; i++) cin >> a[i];
	int mx = a[1];
	dp[1][0] = a[1];
	for (int i = 2; i <= N; i++) {
		dp[i][0] = max(a[i], mx);
		mx = max(mx, a[i]);
	}
	int suff_max[N + 2];
	suff_max[N + 1] = 0;
	for (int i = N; i >= 1; i--) suff_max[i] = max(suff_max[i + 1], a[i]);
	for (int i = 1; i <= N; i++) {
		for (int k = 1; k < min(i, K); k++) {
			dp[i][k] = min(dp[i - 1][k - 1] + suff_max[i], dp[i - 1][k]);
		}
	}
	cout << dp[N][K - 1];
}

컴파일 시 표준 에러 (stderr) 메시지

blocks.cpp: In function 'void freo(str)':
blocks.cpp:22:26: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   22 | void freo(str x) {freopen((x + ".in").c_str(), "r", stdin);freopen((x + ".out").c_str(), "w", stdout);}
      |                   ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
blocks.cpp:22:67: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   22 | void freo(str x) {freopen((x + ".in").c_str(), "r", stdin);freopen((x + ".out").c_str(), "w", stdout);}
      |                                                            ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 0 / 14
• Subtask 2: 0 / 18
• Subtask 3: 0 / 21
• Subtask 4: 0 / 47