Submission #670091

#TimeUsernameProblemLanguageResultExecution timeMemory
670091radalSplit the sequence (APIO14_sequence)C++17
71 / 100
457 ms131072 KiB
#include <bits/stdc++.h> #pragma GCC target("sse,sse2,avx2") #pragma GCC optimize("unroll-loops,O2") #define rep(i,l,r) for (int i = l; i < r; i++) #define repr(i,r,l) for (int i = r; i >= l; i--) #define X first #define Y second #define all(x) (x).begin() , (x).end() #define pb push_back #define endl '\n' #define debug(x) cerr << #x << " : " << x << endl; using namespace std; typedef long long ll; typedef pair<ll,ll> pll; constexpr int N = 1e5+10,mod = 1e9+7,maxm = 210; constexpr ll inf = 1e18+10; inline int mkay(int a,int b){ if (a+b >= mod) return a+b-mod; // if (a+b < 0) return a+b+mod; return a+b; } inline int poww(int a,int k){ if (k < 0) return 0; int z = 1; while (k){ if (k&1) z = 1ll*z*a%mod; a = 1ll*a*a%mod; k >>= 1; } return z; } ll dp[maxm][N],ps[N]; int opt[maxm][N],a[N]; vector<int> ve; vector<pll> baz; ll bar(int i,int j,int k){ return (dp[k][i]-ps[i]*ps[i]-dp[k][j]+ps[j]*ps[j]+ps[j]-ps[i]-1)/(ps[j]-ps[i]); } int main(){ ios :: sync_with_stdio(0); cin.tie(0); int n,k; cin >> n >> k; rep(i,1,n+1){ cin >> a[i]; ps[i] = ps[i-1]+a[i]; dp[1][i] = 0; } k++; rep(i,2,k+1){ ve.clear(); baz.clear(); ve.pb(0); baz.pb({0,inf}); rep(j,1,n+1){ int ind = lower_bound(all(baz),make_pair(ps[j]+1,0ll))-1-baz.begin(); int x = ve[ind]; opt[i][j] = x; dp[i][j] = dp[i-1][x]+ps[x]*(ps[j]-ps[x]); while (!ve.empty()){ x = ve.back(); if (ps[x] == ps[j]){ if (dp[i-1][x]-ps[x]*ps[x] <= dp[i-1][j]-ps[j]*ps[j]){ baz.pop_back(); ve.pop_back(); continue; } break; } ll tmp = bar(x,j,i-1); if (tmp <= baz.back().X){ baz.pop_back(); ve.pop_back(); continue; } break; } if (ve.empty()){ ve.pb(j); baz.pb({0,inf}); continue; } x = ve.back(); if (ps[x] == ps[j]) continue; ll tmp = bar(x,j,i-1); baz.back().Y = tmp; ve.pb(j); baz.pb({baz.back().Y,inf}); } } cout << dp[k][n] << endl; vector<int> ans; int cur = n,cnt = k; while(cnt > 1){ ans.pb(opt[cnt][cur]); cur = opt[cnt][cur]; cnt--; } sort(all(ans)); for (int u : ans) cout << u << ' '; cout << endl; }
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