Submission #669825

#	Time	Username	Problem	Language	Result	Execution time	Memory
669825		rv4102	Knapsack (NOI18_knapsack)	C++17	73 / 100	1096 ms	1460 KiB

knapsack

#include <iostream>
#include <vector>

using namespace std;

int main(){
    int capacity, n;
    cin >> capacity >> n;
    vector<int> price(n), weight(n), copies(n);
    for(int i=0; i<n; i++){
        cin >> price[i] >> weight[i] >> copies[i];
    }

    // // dp[i][j] tells us the maximum profit we can achieve using
    // // a subcollection of first i elements, with j weight
    // vector<vector<vector<int>>> dp(n+1, vector<vector<int>>(2001, vector<int>(capacity+1, 0)));
    // for(int i=0; i<n; i++){
    //     for(int j=1; j<=2000; j++){
    //         for(int k=1; k<=capacity; k++){
    //             if(k >= weight[i]){
    //                 dp[i][j][k] = max(dp[i][j-1][k], dp[i][j-1][k-weight[i]] + price[i]);
    //             }
    //             else{
    //                 dp[i][j][k] = dp[i][j-1][k];
    //             }
    //         }
    //     }

    // }
    vector<int> dp(capacity+1, 0);
    for(int i=0; i<n; i++){
        int max_copies = capacity / weight[i];
        for(int j=1; j<=min(max_copies, copies[i]); j++){
            for(int wt=capacity; wt>=0; wt--){
                if(wt >= weight[i])
                    dp[wt] = max(dp[wt], dp[wt-weight[i]] + price[i]);
                else
                    break;
            }
        }
    }


    // int ans=0;
    // for(int i=0; i<=2000; i++)
    //     ans = max(ans, dp[n-1][i][capacity]);
    // cout << ans << endl;
    cout << dp[capacity] << endl;
}

• Subtask 1: 12 / 12
• Subtask 2: 17 / 17
• Subtask 3: 20 / 20
• Subtask 4: 24 / 24
• Subtask 5: 0 / 27