제출 #669812

#제출 시각아이디문제언어결과실행 시간메모리
669812rv4102Knapsack (NOI18_knapsack)C++17
0 / 100
2 ms304 KiB
#include <iostream> #include <vector> using namespace std; int main(){ int capacity, n; cin >> capacity >> n; vector<int> price(n), weight(n), copies(n); for(int i=0; i<n; i++){ cin >> price[i] >> weight[i] >> copies[i]; } // // dp[i][j] tells us the maximum profit we can achieve using // // a subcollection of first i elements, with j weight // vector<vector<int>> dp(n+1, vector<int>(capacity+1, 0)); // for(int i=1; i<=n; i++){ // for(int j=1; j<=min(2000, copies[i-1]); j++){ // for(int k=1; k<=capacity; k++){ // if(k >= weight[i-1]*j){ // dp[i][k] = max(dp[i-1][k], dp[i-1][k-weight[i-1]*j] + price[i-1]*j); // } // else{ // dp[i][k] = dp[i-1][k]; // } // } // } // } vector<int> dp(capacity+1, 0); for(int i=0; i<n; i++){ for(int j=1; j<=min(2000, copies[i]); j++){ for(int wt=capacity; wt>=0; wt--){ if(wt > weight[i]*j) dp[wt] = max(dp[wt], dp[wt-weight[i]*j] + price[i]*j); } } } cout << dp[capacity] << endl; }
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