이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
#define ff first
#define ss second
#define all(x) x.begin(), x.end()
using ll = long long;
using pii = pair<int,int>;
using pll = pair<ll,ll>;
template<typename T>
using matrix = vector<vector<T>>;
int main(){
cin.tie(0)->sync_with_stdio(0);
int n, k;
cin >> n >> k;
vector<int> v(n+k);
for(int i = 0; i < n+k; i++)
cin >> v[i];
vector<int> sums;
int minmid = max(0,(n+k)/2-k/2-3), maxmid = min(n+k-1,(n+k)/2+k/2+3);
for(int i = minmid; i <= maxmid; i++){
for(int j = i+1; j <= maxmid; j++)
sums.push_back(v[i]+v[j]);//, cout << v[i]+v[j] << '\n';
}
sort(all(sums));
sums.erase(unique(all(sums)),sums.end());
auto findans =[&](int sum){
int p1 = 0, p2 = n+k-1;
vector<int> resp;
while(p1 < p2){
if(v[p1] + v[p2] > sum){
p2--;
continue;
}
if(v[p1] + v[p2] < sum){
p1++;
continue;
}
resp.push_back(v[p1]), resp.push_back(v[p2]);
p1++, p2--;
}
sort(all(resp));
for(int i = 0; i < n; i++)
cout << resp[i] << ' ';
cout << '\n';
};
for(int sum : sums){
int resp = 0;
int p1 = 0, p2 = n+k-1;
int fail = k+1;
while(p1 < p2 && fail){
if(v[p1] + v[p2] > sum){
p2--;
fail--;
continue;
}
if(v[p1] + v[p2] < sum){
p1++;
fail--;
continue;
}
p1++, p2--;
resp++;
}
if(resp >= n/2){
findans(sum);
return 0;
}
}
//exit(1);
}
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