제출 #667855

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
667855		Kaztaev_Alisher	Evacuation plan (IZhO18_plan)	C++17	0 / 100	4051 ms	17888 KiB

plan

//#pragma GCC optomize ("Ofast")
//#pragma GCC optomize ("unroll-loops")
//#pragma GCC target ("avx,avx2,fma")
 
#include <bits/stdc++.h>
#define F first
#define S second
#define pb push_back
#define sz size
#define cl clear
#define ins insert
#define ers erase
#define pii pair < int , int >
#define pll pair< long long  , long long >
#define all(x) x.begin() , x.end()
#define ios ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define file(s) if (fopen(s".in", "r")) freopen(s".in", "r", stdin), freopen(s".out", "w", stdout)
#define tostr(x) to_string(x)
#define tonum(s) atoi(s.c_str())
#define seon(x) setprecision(x)
#define bpop(x) __builtin_popcount(x)
#define deb(x) cerr << #x  << " = " << x << endl;
#define int ll
 
typedef long long ll;
typedef unsigned long long ull;
typedef double db;
typedef long double ldb;
const double PI = 3.14159265;
 
const ll N = 1e5+5;
const ll mod = 1e9+7;
const ll inf = 1e9;
const ll INF = 1e18;
 
using namespace std;
 
ll n , m , q;
ll dp[N];
vector<pll> g[N];
ll road[N];
 
void bfs(){
	set<pll> st;
	int k;
	cin >> k;
	for(int i = 1; i <= n; i++) dp[i] = INF;
	for(int i = 1; i <= k; i++) {
		int u;
		cin >> u;
		dp[u] = 0;
		st.ins({0 , u});
	}
	while(st.sz()){
		int v = st.begin()->S;
		st.ers(st.begin());
		for(pll to : g[v]){
			if(dp[to.F] > dp[v]+to.S){
				st.ers({dp[to.F] , to.F});
				dp[to.F] = dp[v]+to.S;
				st.ins({dp[to.F] , to.F});
			}
		}
	}
}
void solve(){
	cin >> n >> m;
	for(int i = 1; i <= m; i++){
		ll a, b , c;
		cin >> a >> b >> c;
		g[a].pb({b , c});
		g[b].pb({a , c});
	}
	bfs();
	for(int i = 1; i <= n; i++) road[i] = 0;
	cin >> q;
	int i , b;
	cin >> i >> b;
	road[i] = dp[i];
	set<pll> st;
	st.ins({road[i] , i});
	while(st.sz()){
		pll v = *st.begin();
		st.ers(st.begin());
		for(pll to : g[v.S]){
			if(road[to.F] < min(road[v.S] , dp[to.F])){
				st.ers({road[to.F] , to.F});	
				road[to.F] = min(road[v.S] , dp[to.F]);
				st.ins({road[to.F] , to.F});
			}
		}
	}
	cout << road[b] <<"\n";
}
signed main(){
	ios;
	solve();
	return 0;
}
/*
9 12
1 9 4
1 2 5
2 3 7
2 4 3
4 3 6
3 6 4
8 7 10
6 7 5
5 8 1
9 5 7
5 4 12
6 8 2
2
4 7
1
1 5
5 8
1 6
5 3
4 8

*/	

• Subtask 1: 0 / 10
• Subtask 2: 0 / 13
• Subtask 3: 0 / 12
• Subtask 4: 0 / 19
• Subtask 5: 0 / 46