Submission #66417

#	Time	Username	Problem	Language	Result	Execution time	Memory
66417		forestryks	Vudu (COCI15_vudu)	C++14	140 / 140	452 ms	16408 KiB

vudu

///////////////////////////////////////////////////////////////////////////////////////////////
#include <bits/stdc++.h>
using namespace std;

// #define int long long

#define FAST_IO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#define FILE_IO(x) freopen((string(x) + ".in").c_str(), "r", stdin); freopen((string(x) + ".out").c_str(), "w", stdout)
#define f first
#define s second
#define x1 x1qwer
#define y1 y1qwer
#define right right123
#define left left123
#define foreach(it, v) for (auto it : v)
#define rep(it, n) for (int it = 0; it < n; ++it)
#define forin(it, l, r) for (int it = l; it < r; ++it)
#define all(x) x.begin(), x.end()

typedef long long ll;
typedef unsigned long long ull;
typedef double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const double DINF = numeric_limits<double>::infinity();
const ll MOD = 1e9 + 7;
const double EPS = 1e-7;
ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }
mt19937 mmtw_(MOD);
uniform_int_distribution<ll> rd_;
ll randomll() { return rd_(mmtw_);}
ll rnd(ll x, ll y) { return rd_(mmtw_) % (y - x + 1) + x; }
template <class T> T fact(T n) { if (n == 1) return 1; return n * fact(n - 1); }
////////////////////////////////////////////////////////////////////////////////////////////////

const int MAXN = 1e6 + 5;

int n;
ll a[MAXN];
ll t[MAXN];
ll p;

void compress() {
    vector<long long> val(a, a + n);
    sort(val.begin(), val.end());
    val.resize(unique(val.begin(), val.end()) - val.begin());
    for (int i = 0; i < n; ++i) {
        a[i] = lower_bound(val.begin(), val.end(), a[i]) - val.begin();
    }
}

void add(int pos) {
    for (int i = pos; i < n; i = (i | (i + 1))) {
        t[i]++;
    }
}

ll get(int r) {
    ll res = 0;
    for (int i = r; i >= 0; i = (i & (i + 1)) - 1) {
        res += t[i];
    }
    return res;
}

int main() {
    FAST_IO;
    cin >> n;
    rep(i, n) {
        cin >> a[i + 1];
    }
    cin >> p;
    n++;

    partial_sum(a, a + n, a);
    for (int i = 0; i < n; ++i) {
        a[i] = a[i] - p * i;
    }
    compress();

    ll res = 0;
    for (int r = 0; r < n; ++r) {
        res += get(a[r]);
        add(a[r]);
    }

    cout << res << endl;
}

• Subtask 1: 140 / 140