답안 #66375

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
66375 2018-08-10T10:43:28 Z forestryks Savez (COCI15_savez) C++14
0 / 120
128 ms 66560 KB
///////////////////////////////////////////////////////////////////////////////////////////////
#include <bits/stdc++.h>
using namespace std;

// #define int long long

#define FAST_IO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#define FILE_IO(x) freopen((string(x) + ".in").c_str(), "r", stdin); freopen((string(x) + ".out").c_str(), "w", stdout)
#define f first
#define s second
#define x1 x1qwer
#define y1 y1qwer
#define right right123
#define left left123
#define foreach(it, v) for (auto it : v)
#define rep(it, n) for (int it = 0; it < n; ++it)
#define forin(it, l, r) for (int it = l; it < r; ++it)
#define all(x) x.begin(), x.end()

typedef long long ll;
typedef unsigned long long ull;
typedef double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const double DINF = numeric_limits<double>::infinity();
const ll MOD = 1e9 + 7;
const double EPS = 1e-7;
ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }
mt19937 mmtw_(MOD);
uniform_int_distribution<ll> rd_;
ll randomll() { return rd_(mmtw_);}
ll rnd(ll x, ll y) { return rd_(mmtw_) % (y - x + 1) + x; }
template <class T> T fact(T n) { if (n == 1) return 1; return n * fact(n - 1); }
////////////////////////////////////////////////////////////////////////////////////////////////

// struct MyMap : vector<pair<int, int>> {
//     int& operator[](const int v) {
//         auto it = lower_bound(this->begin(), this->end(), make_pair(v, -1));
//         if (it != this->end() && it->first == v) {
//             return it->second;
//         }
//         return this->insert(it, {v, 0})->second;
//     }
// };

const int MAXN = 1e6 + 5;

int n;
int last = 1;
map<int, int> to[MAXN];
int p[MAXN];
vector<string> s;
int term[MAXN];
int res[MAXN];

int get(const string &s, int i) {
    return (s[i] - 'A') + (s[s.size() - 1 - i] - 'A') * 32;
}

int trie_add(const string &s) {
    int n = s.size();
    int v = 0;
    for (int i = 0; i < n; ++i) {
        int ch = get(s, i);

        if (to[v][ch] == 0) {
            to[v][ch] = last;
            p[last] = v;

            v = last++;
        } else {
            v = to[v][ch];
        }
    }

    res[v]++;
    term[v]++;

    int r = res[v];

    while (p[v] != -1) {
        res[p[v]] = max(res[p[v]], term[p[v]] + res[v]);
        v = p[v];
    }

    return r;
}

int main() {
    FAST_IO;
    cin >> n;
    rep(i, n) {
        string a;
        cin >> a;
        s.push_back(a);
    }

    reverse(s.begin(), s.end());

    p[0] = -1;
    int res = 0;
    for (int i = 0; i < n; ++i) {;
        res = max(res, trie_add(s[i]));
    }

    cout << res << endl;
}
# 결과 실행 시간 메모리 Grader output
1 Correct 40 ms 47352 KB Output is correct
2 Incorrect 49 ms 47472 KB Output isn't correct
3 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 49 ms 47728 KB Output is correct
2 Correct 45 ms 47728 KB Output is correct
3 Incorrect 50 ms 52420 KB Output isn't correct
# 결과 실행 시간 메모리 Grader output
1 Correct 58 ms 52420 KB Output is correct
2 Incorrect 58 ms 52420 KB Output isn't correct
3 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 44 ms 52420 KB Output is correct
2 Correct 71 ms 52420 KB Output is correct
3 Incorrect 69 ms 53412 KB Output isn't correct
# 결과 실행 시간 메모리 Grader output
1 Incorrect 68 ms 54304 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 62 ms 55744 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 71 ms 57768 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 86 ms 60668 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 90 ms 64996 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Runtime error 128 ms 66560 KB Memory limit exceeded: We have a known bug that the memory usage is measured incorrectly (possibly because of Meltdown/Spectre patch), so your solution may be correct. Please submit again. Sorry for the inconvenience.
2 Halted 0 ms 0 KB -